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Katyanochek1 [597]
3 years ago
12

Suppose that the cost of a paving stone is $2.50, plus $0.15 for every 4 cubic inches of concrete.

Mathematics
1 answer:
olganol [36]3 years ago
8 0

Answer:

6 different sized paving stones,$16

Complete question:

What if the 360 cubic-inch paving stones are 4 inches thick and any whole number length and width are possible? How many different paving stones could be made? Suppose that the cost of having stone is $2.50, plus $0.15 for every 4 cubic inches of concrete how much would each paving stone cost?

Step-by-step explanation:

V= B x h

B= V / h=> 360 / 4  

B= 90 sq inch

Considering the factors of 90: 1,2,3,5,6,9,10,15,18,30,45,90

Now, make table with base height and volume for each pair of factors. (see figure in the attachment)

We'll have 6 different sized paving stones.

As each stone has a vol of 360 inches³. Diving by 4 in order to find how many 4 inch³ per stone

Concrete=$0.15 x (360/4) => $0.15 x 90

Concrete= $13.5

The cost of the stone plus the concrete will be:

cost= $2.50 + concrete

cost= $2.50 + $13.5

cost=$16

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Step-by-step explanation:

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The number of peas on Pauline's plate, 40, is 13 greater than the number on Doris's plate. How many peas are on Doris's plate?
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Step-by-step explanation:

Let the number of peas in Doris plate be x

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Jim bought a fishing rod for $42. The price was 70% of the original price. What was the original price?
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zlopas [31]

Answer:

132,090.30

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Determine the radius of convergence of the following power series. Then test the endpoints to determine the interval of converge
tresset_1 [31]

Answer:

Radius of the convergence is R = \frac{1}{21}

and,

The Interval of convergence is -\frac{1}{21}

Step-by-step explanation:

Given function : Σ(21x)^k

Now,

Using the ratio test, we have

R = \lim_{n \to \infty} |\frac{21x^{k+1}}{21x^{k}}|

or

R = \lim_{n \to \infty} |\frac{21x^{k}\times21x^{1}}{21x^{k}}|

or

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for convergence R|x| < 1

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-\frac{1}{21}

and,

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