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3 years ago

Suppose that the cost of a paving stone is $2.50, plus $0.15 for every 4 cubic inches of concrete.

Mathematics

1 answer:

olganol [36]3 years ago

8 0

Answer:

6 different sized paving stones,$16

Complete question:

What if the 360 cubic-inch paving stones are 4 inches thick and any whole number length and width are possible? How many different paving stones could be made? Suppose that the cost of having stone is $2.50, plus $0.15 for every 4 cubic inches of concrete how much would each paving stone cost?

Step-by-step explanation:

V= B x h

B= V / h=> 360 / 4

B= 90 sq inch

Considering the factors of 90: 1,2,3,5,6,9,10,15,18,30,45,90

Now, make table with base height and volume for each pair of factors. (see figure in the attachment)

We'll have 6 different sized paving stones.

As each stone has a vol of 360 inches³. Diving by 4 in order to find how many 4 inch³ per stone

Concrete=$0.15 x (360/4) => $0.15 x 90

Concrete= $13.5

The cost of the stone plus the concrete will be:

cost= $2.50 + concrete

cost= $2.50 + $13.5

cost=$16

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$=\frac{8^{(2/3)}27^{(1/3)}p^{(1)}q^{(2)}q^{(1/3)}}{p^{(4)}}$ Rearranged for you to see the like terms

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