What are the two types of percent of change
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We have that
csc ∅=13/12
sec ∅=-13/5
cot ∅=-5/12
we know that
csc ∅=1/sin ∅
sin ∅=1/ csc ∅------> sin ∅=12/13
sec ∅=-13/5
sec ∅=1/cos ∅
cos ∅=1/sec ∅------> cos ∅=-5/13
sin ∅ is positive and cos ∅ is negative
so
∅ belong to the II quadrant
therefore
<span>the coordinates of point (x,y) on the terminal ray of angle theta are
</span>x=-5
y=12
the answer is
point (-5,12)
see the attached figure
csc ∅=13/12
sec ∅=-13/5
cot ∅=-5/12
we know that
csc ∅=1/sin ∅
sin ∅=1/ csc ∅------> sin ∅=12/13
sec ∅=-13/5
sec ∅=1/cos ∅
cos ∅=1/sec ∅------> cos ∅=-5/13
sin ∅ is positive and cos ∅ is negative
so
∅ belong to the II quadrant
therefore
<span>the coordinates of point (x,y) on the terminal ray of angle theta are
</span>x=-5
y=12
the answer is
point (-5,12)
see the attached figure
The center of the dilation is the origin, and the scale factor is 2.
To find the coordinates of the points under this transformation, it is enough to multiply both coordinates of the points X, Y, and Z by 2.
Take a look at the dilation of point Z. To get to Z', both the x and y coordinate of Z must be multiplied by 2.
So, the coordinates are:
X'(8, 0); Y'(6, 4); Z'(4, -4).
To find the coordinates of the points under this transformation, it is enough to multiply both coordinates of the points X, Y, and Z by 2.
Take a look at the dilation of point Z. To get to Z', both the x and y coordinate of Z must be multiplied by 2.
So, the coordinates are:
X'(8, 0); Y'(6, 4); Z'(4, -4).