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ad-work [718]
4 years ago
14

Which of these is a characteristic of science?

Chemistry
1 answer:
kolezko [41]4 years ago
3 0

Answer:

It follows a clearly laid out method.

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10 points<br><br> How many more oxygen atoms are in 3Mg3(PO4)2 than in 4Al2O3?
Feliz [49]

Answer:

12 more oxygen

Explanation:

An atom is the smallest particles that can take part in a chemical reaction

The given compounds are:

        3Mg₃(PO₄)₂  

 Number of oxygen atoms  = 3[2 x 4]  = 24 oxygen atoms

For;

             4Al₂O₃;

   Number of oxygen atoms  = 4 x 3  = 12 oxygen atoms

In   3Mg₃(PO₄)₂  , there are 24  - 12  = 12 more oxygen atoms than in  4Al₂O₃;

6 0
3 years ago
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Describe nucleus of atom​
tresset_1 [31]

Answer:

the nucleus is made up of protons and neutrons

5 0
3 years ago
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According to the scheme below, How much energy is required to evaporate 54.06 g water (Molecular weight of water is 18.02 g/mol)
Anna71 [15]

Answer:

what

Explanation:

6 0
3 years ago
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The greatest benefit of species diversity is that
6 0
3 years ago
Find an expression for the change in entropy when two blocks of the same substance of equal mass, one at the temperature Th and
Gre4nikov [31]

Explanation:

Relation between entropy change and specific heat is as follows.

            \Delta S = C_{p} log (\frac{T_{2}}{T_{1}})

The given data is as follows.

     mass = 500 g,         C_{p} = 24.4 J/mol K

     T_{h} = 500 K,          T_{c} = 250 K               

   Mass number of copper = 63.54 g /mol

Number of moles = \frac{mass}{/text{\molar mass}}

                                 = \frac{500}{63.54}

                                 = 7.86 moles

Now, equating the entropy change for both the substances as follows.

     7.86 \times 24.4 \times [T_{f} - 250] = 7.86 \times 24.4 \times [500 -T_{f}]

       T_{f} - 250 = 500 - T_{f}

          2T_{f} = 750

So,       T_{f} = 375^{o}C

  • For the metal block A,  change in entropy is as follows.

         \Delta S = C_{p} log (\frac{T_{2}}{T_{1}})

              = 24.4 log [\frac{375}{500}]

              = -3.04 J/ K mol

  • For the block B,  change in entropy is as follows.

         \Delta S = C_{p} log (\frac{T_{2}}{T_{1}})

                  = 24.4 log [\frac{375}{250}]

                  = 4.296  J/Kmol

And, total entropy change will be as follows.

                       = 4.296 + (-3.04)

                      = 1.256 J/Kmol

Thus, we can conclude that change in entropy of block A is -3.04 J/ K mol  and change in entropy of block B is 4.296  J/Kmol.

8 0
3 years ago
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