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PilotLPTM [1.2K]
2 years ago
12

Convert 44.8 liters of CO2 into particles of CO2​

Chemistry
1 answer:
jonny [76]2 years ago
5 0

Answer:

1.2044 x 10^24 particles

Explanation:

Assuming this is<u> STP</u>....then this is 2 moles    ( each mole = 22.4 L/mole)

  2 moles = 2 * 6.022 x 10^23  = 1.2044 x 10^24

               

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A titration is performed on a 25.0 mL sample of calcium hydroxide. A volume of
slamgirl [31]

Answer:

\boxed {\boxed {\sf 0.28 \ M}}

Explanation:

Titration is a method used to determine the concentration of a substance. The  formula for this is:

M_AV_A= M_BV_B

Where M is the molarity of the acid or base and V is the volume of the acid or base.

We know that 46.0 milliliters of a 0.15 molar solution of nitric acid wereused in the titration. 25.0 milliliters of solution of calcium hydroxide of unknown molarity were also used.

\bullet \  M_A= 0.15 \ M \\\bullet \  V_A= 46.0 \ mL\\\bullet \  V_B= 25.0 \ mL

Substitute these known values into the formula.

0.15 \ M * 46.0 \ mL= M_B * 25.0 \ mL

We are solving for the molarity of the base, so we must isolate the variable M_B. It is being multiplied by 25.0 milliliters. The inverse operation of multiplication is division, so we divide both sides of the equation by 25.0 mL.

\frac {0.15 \ M * 46.0 \ mL}{25.0 \ mL}= \frac{M_B * 25.0 \ mL}{25.0 \ mL}

\frac {0.15 \ M * 46.0 \ mL}{25.0 \ mL}= M_B

The units of milliliters (mL) cancel.

\frac {0.15 \ M * 46.0 }{25.0}=M_B

\frac {6.9}{25.0 } \ M =M_B

0.276 \ M = M_B

The original measurements have 2 or 3 significant figures. We always round our answer to the least number of sig figs, which is 2. For the number we calculated, that is the hundredths place. The 6 in the thousandths place tells us to round the 7 up to an 8.

0.28 \ M \approx M_B

The concentration of calcium hydroxide is approximately <u>0.28 M.</u>

6 0
3 years ago
magnesium hydroxide is 54.87% oxygen by mass. how many grams of oxygen are in 175 g sample of the compound
klasskru [66]

Answer:

96 g of O

Explanation:

Mg(OH)₂ → Magnesium hydroxide

Molar mass → 24.3g/mol . 1 + 16g/mol . 2 + 1g/mol . 2 = 58.3 g/mol

We determine the moles of hydroxide → 175 g . 1mol/58.3g = 3 moles

Let's make some rule of three:

In 100 g of compound we have 54.87 g of O

In 58.3 g of compound we may have (58.3 . 54.87) / 100 = 32 g

So, 1 mol of hydroxide has 32 g of oxygen

3 moles of hyroxide may have (3 .32)/1 = 96 g of O

4 0
3 years ago
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