Question

a school netball team won ten matches , lost four and drew 1/8 of the total played . how many matches were drawn and what fraction did the team win ?

Answer 1

The school net ball team drew 2 matches. The team won $\frac{5}{8}$ of total matches played

Solution:

Given, A school netball team won ten matches, lost four and drew $\frac{1}{8}$ of the total played

Let the total number of matches played be "n"

Number of matches drawn = $\frac{1}{8}$ of n

Total matches played = number of won matches + number of lost matches + number of drawn matches

$\begin{array}{l}{n=10+4+\frac{1}{8} n} \\\\ {n-\frac{1}{8} n=10+4}\end{array}$

Taking "n" as common from left hand side,

$\begin{array}{l}{\mathrm{n}\left(1-\frac{1}{8}\right)=14} \\\\ {\mathrm{n} \times \frac{8-1}{8} \quad 14} \\\\ {\mathrm{n} \times \frac{7}{8}=14} \\\\ {\mathrm{n}=16}\end{array}$

So, they played 16 matches in total

Number of matches drawn = $\frac{1}{8}$ of n = $\frac{1}{8} \times 16 = 2$$\text { Fraction of won matches }=\frac{\text { number of matches won }}{\text { number of matches played }}=\frac{10}{16}=\frac{5}{8}$

$\text { Hence, the team drew } 2 \text { matches and won } \frac{5}{8} \text { of total played matches. }$