Answer: P(x) = {(x-4)^2} (x) (x+4)
Step-by-step explanation:
Let's start with the multiplicity of 2;
At multiplicity of 2; x=4.
Therefore, x - 4 is a factor of the function P(x).
Since it has a multiplicity of 2, we will rewrite the factor as (x-4)^2
Now for the multiplicity of 1.
At this multiplicity of 1, x= 0 and - 4.
Therefore, the factors are x-0 and x+4
Since multiplicity of 1, the factors remain as they are without any additional root on top.
Therefore, the factors of the polynomial p(x) are (x-4)^2 and x and x+4.
And solution of P(x) in factor form will be: P(x) = {(x-4)^2} (x) (x+4)
