5.8/ sqrt 80=0.648 I think you are asking for the standard margin
Hope this works
Answer:
900
Step-by-step explanation:
Hope this helps!
Answer:
The 95% confidence interval for the proportion of corporations preferring a nonsmoking candidate is (0.2328, 0.2872)
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 95% confidence interval for the proportion of corporations preferring a nonsmoking candidate is (0.2328, 0.2872)
Answer:
b, c, and d are solutions
Step-by-step explanation:
3x - 2 < 2 - 2x
5x - 2 < 2
5x < 4
x < 4/5
b) 1/2 < 4/5 true
c) -3 < 4/5 true
d) 2/3 < 4/5 true