Answer:
Step-by-step explanation:

If a <u>term</u> doesn't have a <u>coefficient</u> , it is considered that the coefficient is 1

Why is it considered that the coefficient is 1?
Remember that any term multiplied by 1 remains the same:

Step 1
The equality can be read in the other way as well , so any term can be written as a product of 1 and itself:

Step 2
Usually, we don't need to write multiplication sign between the coefficient and the variable , so the simpler form is:

That is why we can write the term without the coefficient as a term with coefficient 1.
Let's go back to your problem now
Collect l<u>ike terms </u>by adding their <u>coefficients</u>

Add the numbers

PLEASE MARK ME AS BRAINLIEST