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almond37 [142]
3 years ago
15

True or false ? If a parallelogram is inscribed in a circle , it must be a square

Mathematics
2 answers:
TEA [102]3 years ago
5 0

The answer is TRUE. The parallelogram must be a rectangle

Grace [21]3 years ago
3 0

Answer:

False

Step-by-step explanation:

APEX

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Is the following statement always, sometimes, or never true? “The supplement of an acute angle is an obtuse angle.” Explain your
balu736 [363]

Answer:

Always

Step-by-step explanation:

An acute angle is an angle that is less than 90. Supplementary angles add up to 180.

So 180-89= 91

An obtuse angle is any angle that is greater than 90.

Here's a link to a better explanation.

brainly.com/question/14180317

7 0
3 years ago
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Solve by applying the counting principle. James is choosing a Four-digit Passcode for his smartphone. How many different Passcod
EleoNora [17]

Answer:

10k.

Step-by-step explanation:

1) if for the 1st position can be used 0-9 digits (10 digits), for the 2d - 0-9 digits, for the 3d - 0-9 digits and for the 4th - 0-9 digits, then

2) the required number of pwd is: 10*10*10*10=10⁴=10000.

4 0
2 years ago
Write the exponential equation for the given situation. A tennis tournament starts with 128 participants. Each round, half of th
inysia [295]

Answer:

y= 128(1-.5)^t

Step-by-step explanation:

6 0
3 years ago
(1 ÷ x- 1)+(2÷ x+2)=(3÷2) solve and check for extraneous solutions
Sliva [168]
\frac{1}{x-1}+ \frac{2}{x+2}= \frac{3}{2}
\frac{1(x+2)}{(x-1)(x+2)}+ \frac{2(x-1)}{(x+2)(x-1)}= \frac{3(x-1)(x+2)}{2}
\frac{x+2+2(x-1)}{(x-1)(x+2)}= \frac{3(x-1)(x+2)}{2}
\frac{x+2+2x-1}{(x-1)(x+2)}= \frac{3(x-1)(x+2)}{2}
\frac{3x+1}{(x-1)(x+2)}= \frac{3(x^2+x-2)}{2}
\frac{}{(x-1)(x+2)}= \frac{3x^2+3x-6)}{2}
\frac{3x+1}{(x^2+x-2)}= \frac{3x^2+3x-6)}{2}
\frac{2(3x+1)}{2(x^2+x-2)}= \frac{3x^2+3x-6)(x^2+x-2)}{2(x^2+x-2)}
\frac{2(3x+1)}{2(x^2+x-2)}-\frac{3x^2+3x-6)(x^2+x-2)}{2(x^2+x-2)}=0
\frac{2(3x+1)-3x^2+3x-6}{2(x^2+x-2)}=0

this will be continued
5 0
4 years ago
Susan divides the fraction LaTeX: \frac{5}{8}5 8by LaTeX: \frac{1}{16}1 16. Her friend Robyn divides LaTeX: \frac{5}{8}5 8by LaT
marissa [1.9K]

Given:

Susan divides the fraction \dfrac{5}{8} by \dfrac{1}{16}.

Her friend Robyn divides \dfrac{5}{8} by \dfrac{1}{32}.

To find:

The quotient of Susan and Robyn.

Solution:

Susan divides the fraction \dfrac{5}{8} by \dfrac{1}{16}.

\dfrac{\dfrac{5}{8}}{\dfrac{1}{16}}=\dfrac{5}{8}\times \dfrac{16}{1}

\dfrac{\dfrac{5}{8}}{\dfrac{1}{16}}=\dfrac{80}{8}

\dfrac{\dfrac{5}{8}}{\dfrac{1}{16}}=10

So, Susan's quotient is 10.

Her friend Robyn divides \dfrac{5}{8} by \dfrac{1}{32}.

\dfrac{\dfrac{5}{8}}{\dfrac{1}{32}}=\dfrac{5}{8}\times \dfrac{32}{1}

\dfrac{\dfrac{5}{8}}{\dfrac{1}{32}}=5\times 4

\dfrac{\dfrac{5}{8}}{\dfrac{1}{32}}=20

So, Robyn's quotient is 20.

Since 20>10, therefore, Robyn will get greater quotient.

3 0
3 years ago
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