It is given that ️PQR & ️UVW are congruent to each other. According to CPCT, the corresponding angles in 2 triangles willl have the same measure. So, ∠R = ∠W, i.e, (10x - 18)° = 8x°

$\mathfrak{10x - 18 = 8x}$

$\mathfrak{10x - 8x = 18}$

$\mathfrak{2x = 18}$

$\mathfrak{x = \dfrac{18}{2}}$

$\underline{\mathfrak{x = 9}}$

Measure of ∠R :

$\mathfrak{8x}$

$\mathfrak{8(9)}$

$\boxed{\mathfrak{72^{\circ}}}$

ღ ꪑ꠸᥅ꫀꪊ

7 0

2 years ago

Evaluate 6+x6+x6, plus, x when x=3?

vampirchik [111]

Answer:

Step-by-step explanation:

x=3

6+x6+x6

6+(3)6+(3)6

6=6

(3)6=18

6+18+18

24+18

Hope this helps ;) ❤❤❤

8 0

2 years ago

Read 2 more answers

X - y = 2 4x – 3y = 11

swat32

Answer:

For x - y = 2

You need to find x or y in one of the equations and then substitute that into the other.

So we have;

x-y=2

4x-3y=11

We will take the first equation and find x;

x-y=2

add y to both sides;

x-y+y=2+y

x=2+y

Now we take that answer and substitute it forx in the other equation;

4(2+y)-3y=11

8+4y-3y=11

8+y=11

y=3

Now we have what y equals, so we use it in the first equation to find x;

x-3=2

x=5

So we have;

x=5; y=3

Hope you understand!

And for 4x – 3y = 11

Multiply the first equation by 2 and the second by 3 so that there are the same number of y's in each:

8x - 6y = 22 ...(3)

30x + 6y = -3 ...(4)

Now add (3) and (4) term by term:

38x + 0 = 19

38x = 19

or x = 1/2

Put this back into equation (1)

4*(1/2) - 3y = 11

2 - 3y = 11

Subtract 2 from both sides:

-3y = 9

Divide both sides by -3

y = -3

6 0

2 years ago

Read 2 more answers