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sammy [17]
3 years ago
10

In describing a new problem you are having with your computer, your boss interrupts and states, I had the same problem last week

. It's something to do with the network." Which conceptual block could be inhibiting your boss's creative problem-solving approach?"
Computers and Technology
2 answers:
laila [671]3 years ago
6 0

Answer:

Constancy

Explanation:

Problems encountered by people in managerial positions are different. However, there comes a time when a person fails to find solutions to the problems that crop up.

When a problem arises, there are obstacles that are referred to as conceptual blocks and constrain the way one perceives the solution. One of the problems is constancy. This conceptual block takes place when one person becomes committed to one solution to solve a problem. The issue is that people will always be consistent in the way they solve problems.

Anna007 [38]3 years ago
5 0

Answer:

Stereotyping

Explanation:

According to my research on information technology, I can say that based on the information provided within the question it can be said that your boss is exhibiting Stereotyping which could be inhibiting his creative problem-solving approach. Just like in psychology, stereotyping is over-generalized belief about a particular something. Which in this case since his boss saw a similarity in the problem with another problem he previously had, he automatically assumed he knew the cause and how to fix it.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

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Check the explanation

Explanation:

To solve the question above, we will be doing some arithmetic and bit wise operations on enum values. in addition to that, we are asserting the array with INTCOUNT  and also printing the size of array i.e 12 and we are adding BIG_COUNT enum value to 5 and the result is 25.

#include<stdio.h>

enum EnumBits

{

ONE = 1,

TWO = 2,

FOUR = 4,

EIGHT = 8

};

enum Randoms

{

BIG_COUNT = 20,

INTCOUNT = 3

};

int main()

{

// Basic Mathimatical operations

printf("%d\n",(ONE + TWO)); //addition

printf("%d\n",(FOUR - TWO)); //subtraction

printf("%d\n",(TWO * EIGHT)); //multiplication

printf("%d\n",(EIGHT / TWO)); //division

// Some bitwise operations

printf("%d\n",(ONE | TWO)); //bitwise OR

printf("%d\n",(TWO & FOUR)); //bitwise AND

printf("%d\n",(TWO ^ EIGHT)); //bitwise XOR

printf("%d\n",(EIGHT << 1)); //left shift operator

printf("%d\n",(EIGHT >> 1)); //right shift operator

// Initialize an array based upon an enum value

int intArray[INTCOUNT]; // declaring array

// Have a value initialized be initialized to a static value plus

int someVal = 5 + BIG_COUNT; //adding constant and BIG_COUNT variable

printf("%d\n",someVal); //value will be 25

printf("%d",sizeof(intArray)); //value will be 12

return 0;

}

Kindly check the attached image below for the Code and Output Screenshots:

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