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Harrizon [31]
3 years ago
15

What is the identity of a 100. g sample of metal that, upon absorbing 4680 J of heat, increases in temperature by 52.0°C?

Chemistry
1 answer:
krok68 [10]3 years ago
3 0

The metal is aluminium

<u>Explanation:</u>

Given:

Heat, q = 4680 J

Mass, m = 100g = 0.1kg

ΔT = 52°C

sample = ?

We know:

q = mcΔT

On substituting the value we get:

4680 = 0.1 X c X(52)\\\\c = \frac{4680}{5.2} \\\\c = 900 J/Kg^oC

Thus, the metal is aluminium which has a specific heat capacity of 900 J/kg°C

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Answer:- 3333 g of solution.

Some of the question part is missing here. It would be like, "Determine the mass in grams of each NaCl solution that contains 1.5 g of NaCl.

(i) 0.045% NaCl by mass

Solution:- 0.045% NaCl by mass means 0.045 g of NaCl are present in 100 g of solution. 1.5 g of NaCl would be present in how many grams of solution?

We could solve this using proportions...

(0.045/100) = (1.5/X)

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here is your answer >>>

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