The rate of effusion of ammonia (NH₃) in the same apparatus is 63.3 cm/min
<h3>Graham's law of diffusion </h3>
This states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass i.e
R ∝ 1/ √M
R₁/R₂ = √(M₂/M₁)
<h3>How to determine the rate of ammonia (NH₃) </h3>
- Rate of HCl (R₁) = 43.2 cm/min
- Molar mass of HCl (M₁) = 1 + 35.5 = 36.5 g/mol
- Molar mass of NH₃ (M₂) = 14 + (3×1) = 17 g/mol
R₁/R₂ = √(M₂/M₁)
43.2 / R₂ = √(17 / 36.5)
Cross multiply
43.2 = R₂ × √(17 / 36.5)
Divide both side by √(17 / 36.5)
R₂ = 43.2 / √(17 / 36.5)
R₂ = 63.3 cm/min
Thus, the rate of effusion of ammonia is 63.3 cm/min
Learn more about Graham's law of diffusion:
brainly.com/question/14004529
Answer:
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Explanation:
<h2>
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Answer:
iodine
Explanation:
<em>The substance that can break easily from the list of substances is the </em><em>iodine</em><em>.</em>
<u>Iodine exists as a molecular solid and hence, the molecules are held together by weak Van Der Waal's forces. Iodine thus has characteristic properties of typical molecular solids which include being able to be broken into pieces easily (brittle), low melting and boiling points, insolubility in water, among other properties.</u>
The characteristics of iodine are unlike sodium, calcium, and copper that exist as metal which is hard, tough with high tensile strengths.
Answer:
13-b
Explanation:
because 13-b is close to a and 12
