Question

25e² + n 4= 20edon't know what to do so please help

Answer 1

Answer:

see explanation

Step-by-step explanation:

This is a quadratic equation

Rearrange into standard form : ax² + bx + c = 0 : a ≠ 0

subtract 20e from both sides

25e² - 20e + 4 = 0 ← in standard form

This is a perfect square of the form

(a - b)² = a² - 2ab + b²

25e² = (5e)² ⇒ a = 5e and 4 = 2² ⇒ b = 2, and

- 2ab = - 2 × 5e × 2 = - 20e, hence

25e² - 20e + 4 = (5e - 2)²

⇒ (5e - 2)² = 0 ⇒ e = $\frac{2}{5}$ with multiplicity 2