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lesya [120]
3 years ago
6

During the course of a physical exam, a physician suspects his patient may be depressed. In order to explore this diagnostic pos

sibility, the physician uses a "brief screening device" for depression. The doctor probably:
Biology
1 answer:
tangare [24]3 years ago
6 0

Answer: asked the patient two questions about feelings of hopelessness and feelings related to the enjoyment of activities

Explanation:

Hopelessness is an emotional context featured by a lack of hope, passion, and optism. It is expressed as a symptom of varying behavioral and mental health problems, including depression, bipolar, anxiety, eating disorders and among others.

In the other hand, the test on feelings related to enjoyment was done to evaluate the the emotions of pleasure from the individual’s engagements.

However, the physician carried out the two tests on his patient to know whether he's depressed or not.

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The most important difference between primary cells and secondary cells is Select only the best answer: primary cells exhibit a
torisob [31]

Hi there! This question is a bit confusing.

Primary cells more of have one "star" quality; they are not rechargable. Think of them like a battery in a TV remote! You replace them, they can't recharge.

Secandary cells, though, can be electrically recharged! Like your phone battery, plug it in and a few hours later, full battery.

Your answer would be "Secondary cells are rechargable"

Have a great rest of your day!

4 0
2 years ago
Is diffusion active or passive
Dmitry_Shevchenko [17]

Answer:

Diffusion is a passive process

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3 years ago
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A recessive allele causes phenylketonuria (PKU) when homozygote. If the frequency of the recessive allele is 0.05 in the populat
Radda [10]

Answer:

0.095

Explanation:

Phenylkentonuria is a disease caused by a recessive allele.

The frequency of the recessive allele + the frequency of the dominant allele equals 1.

The frequency of the recessive allele is q = 0.05

The frequency of the dominant allele then is p = 1  - q = 0.95

If people mate randomly, the frequency of the homozygous dominant genotype will be p², the frequency of the heterozygous genotype will be 2pq and the frequency of the homozygous recessive genotype will be q² .

2pq=2× 0.05 × 0.95

2pq=0.095

The heterozygote frequency in the population is 0.095

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Thyroid Gland

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