<h2>Koch's postulates </h2>
Explanation:
Koch formulated a set of criteria that could be used to identify the pathogen responsible for a specific disease and these criteria came to be known as Koch’s postulates:
The organism must be regularly associated with the disease and its characteristic lesions
The organism must be isolated from the diseased host and grown in culture
The disease must be reproduced when a pure culture of the organism is introduced into a healthy, susceptible host
The same organism must be re-isolated from the experimentally infected host
In the given hypothesis , Koch's postulates could be used as:
1) identify pathogen associated with disease 2) isolate or purify pathogen 3) test subject gets pathogen 4) same disease/ causes liver disease or not
Answer:
- GLYCOLYSIS :- Glycolysis is the metabolic pathway that converts glucose C₆H₁₂O₆, into pyruvic acid, CH₃COCOOH. The free energy released in this process is used to form the high-energy molecules adenosine triphosphate and reduced nicotinamide adenine dinucleotide
- PRODUCTS :- Glycolysis produces 2 ATP, 2 NADH, and 2 pyruvate molecules: Glycolysis, or the aerobic catabolic breakdown of glucose, produces energy in the form of ATP, NADH, and pyruvate, which itself enters the citric acid cycle to produce more energy.
- INPUT:- Glycolysis is the first step in cellular respiration, occurring in all living cells. Overall, the input for glycolysis is one glucose, two ATP and two NAD+ molecules giving rise to two pyruvate molecules, four ATP and two NADH.
- BREAKDOWN:- During glycolysis, glucose ultimately breaks down into pyruvate and energy; a total of 2 ATP is derived in the process (Glucose + 2 NAD+ + 2 ADP + 2 Pi --> 2 Pyruvate + 2 NADH + 2 H+ + 2 ATP + 2 H2O). The hydroxyl groups allow for phosphorylation. The specific form of glucose used in glycolysis is glucose 6-phosphate
- STAGES:-
- Reaction 1: glucose phosphorylation to glucose 6-phosphate.
- Reaction 2: isomerization of glucose 6-phosphate to fructose 6-phosphate
- Reaction 3: phosphorylation of fructose 6-phosphate to fructose 1,6-bisphosphate
- Reaction 4: cleavage of fructose 1,6-bisphosphate into two three-carbon fragments.
Explanation:
<h2>HOPE IT HELPS YOU ITZ ADMIRER </h2>
I think it wouldn’t be dead until it looses all of its color and is able to crumple in your fingertips. So basically, it isn’t dead yet when it is wilted. But Its getting to the stage of being dead (like how old people are at that stage of their life where they will pass away soon).
To put it simply, the flower is not dead yet, it’s just “old” :D
Pacinian corpuscles are rapidly-adapting, deep receptors that respond to deep pressure and high-frequency vibration.