Answer:
12
Step-by-step explanation:
The reason why AC cannot be 12 because AB is 12, and by looking at the graph AC is obviously longer.
The answer is A
set 13/20=x/100 13x100 is 1300 divided by 20 is 65.
65/100 is 0.65 as a decimal
Total = 36oz
Amount of 18% solution = x
Amount of 9% solution = 36 - x
Using the fact that (amount of solution) * (percent HCl) = amount HCl we can set up an expression for the amount HCl in a mixture of 18% and 9% solutions with a total volume of 36oz.
Amount of HCl = x*0.18 + (36 - x)*0.09
If we divide this by the amount of solution we get percent HCl, and we have a target of 10% HCl. Now we have an equation to solve,
[x*0.18 + (36 - x)*0.09]/36 = 0.1
x*0.09 + 3.24 = 3.6
.09x = 0.36
x = 4
Therefore,
4 ounces of 18% HCl solution and 32 ounces of 9% HCl solution
Check:
[(4*.18) + (.09*32)]/36 = 0.1?
0.1 = 0.1 Yes.
Change in April's weight is -7
<em><u>Solution:</u></em>
Let the initial weight be "x"
April lost 5 pounds in her first week of college
First week = lost 5 pounds
Therefore, x - 5
Over the next three weeks she lost 3 pounds, gained 2 pounds, and then lost 1 pound
<em><u>Next three week:</u></em>
Lost 3 pound
Gained 2 pound
Lost 1 pound
<em><u>Therefore, weight after 4 weeks is given as:</u></em>
x - 5 - 3 + 2 - 1 = x -7
After 4 week, the weight is x - 7
<em><u>The change in April weight is given as:</u></em>
Weight after 4 week - initial weight = x - 7 - x = -7
Thus change in April's weight is -7 (Negative sign represents loss in weight )
The area of the composite figure is 
Explanation:
From the given figure, we can see that the area of the composite figure = area of the rectangle + area of the triangle.
Area of the rectangle
:
The formula is given by

where
and 
Substituting, we have,

Thus, the area of the rectangle = 
Area of the triangle
:
The formula is given by

where 
and 
Substituting, we have,

Thus, the area of the triangle = 
Area of the composite figure = Area of the rectangle + area of the triangle
Area of the composite figure = 
Thus, the area of the composite figure is 