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Novosadov [1.4K]
2 years ago
14

Please help!!! Which expression is equivalent to (3m^-1n^2)^4/(2m^-2n)^3

Mathematics
2 answers:
Alik [6]2 years ago
8 0
<h3>The answer on edg is B!</h3>

Hope this helps!

Elza [17]2 years ago
7 0
\text{Use:}\\\\(a\cdot b)^n=a^nb^n\\\\(a^n)^m=a^{n\cdot m}\\\\\dfrac{a^n}{a^m}=a^{n-m}

\dfrac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}=\dfrac{3^4(m^{-1})^4(n^2)^4}{2^3(m^{-2})^3n^3}=\dfrac{81m^{-4}n^8}{8m^{-6}n^3}\\\\=10.125m^{-4-(-6)}n^{8-3}=10.125m^2n^5
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Tomas and Tasha were hiking at a speed of 3.5 mph. On their way back, they were tired and their speed was 2 mph. How long was th
Anna35 [415]

 To get the length of the route use the expression for speed,

Distance = Speed × Time

Length of the route is 7 miles.

It's given in the question,

 Speed of Tomas and Tasha initially = 3.5 mph

Therefore, distance travelled by both with the speed of 2 mph one way will be,

 Distance = 3.5t [Here, t = time ]

Speed of both while coming back = 2 mph

And the time taken = t + (1 hour 30 minutes)

                                 = (t + 1.5) hours

Therefore, distance travelled while coming back = Speed × Time

                                                                                  = 2(t + 1.5)

Since, length of the route is same both ways,

3.5t = 2(t + 1.5)

3.5t = 2t + 3

3.5t - 2t = 3

1.5t = 3

t = 2 hours

Now substitute the value of t in the expression to get the distance of the route,

Distance = 3.5t

               = 3.5 × 2

               = 7 miles

 Therefore, route was 7 miles long.

Learn more,

brainly.com/question/1955818

7 0
2 years ago
Read 2 more answers
Please hellllllllppppppppppppppppppppppppppp
vitfil [10]

Answer:

21^{10}

Step-by-step explanation:

First, multiply the 3 and the 7 together, and then "multiply" the exponents -8 and 3. (However, when "multiplying exponents, you're really just adding them together: -8 + 5)

(21^{-5})^2

Then, multiply the -5 and -2 together, giving you:

21^{10}

5 0
3 years ago
Which functions have an axis of symmetry of x = -2? Check all that apply. A. f(x) = x^2 + 4x + 3 B. f(x) = x^2 - 4x - 5 C. f(x)
Snowcat [4.5K]

Answer:

A. f(x) = x^2 + 4x + 3

D. f(x) = -2x^2 - 8x + 1

Step-by-step explanation:

The axis of symmetry is found by h = -b/2a  where ax^2 +bx +c

A. f(x) = x^2 + 4x + 3

  h = -4/2*1 = -2    x=-2

B. f(x) = x^2 - 4x - 5

h = - -4/2*1 = 4/2 =2  x=2  not -2

C. f(x) = x^2 + 6x + 2

h =  -6/2*1 = -3/2 =  x=-3/2  not -2

D. f(x) = -2x^2 - 8x + 1

h = - -8/2*-2 = 8/-4 =-2  x=-2  

E. f(x) = -2x^2 + 8x - 2

h = - 8/2*-2 = -8/-4 =2  x=2  not -2

7 0
2 years ago
7/8 subtract 1/2 equals. and explain how you got your answer
puteri [66]
3/8 because you find the common denominator
8: 8,16,24,32
2: 2,4,6,8
1/2=4/8
7/8-4/8
So the answer is 3/8
You can try to find the denominator and then change the denominator+numerator.
6 0
3 years ago
In the following system of equations, determine whether the system has a unique
Rina8888 [55]

Answer:

the system has a unique solution

Step-by-step explanation:

Start with an equation of a line in standard form,

ax + by = c

Solve it for y to put it into the slope-intercept form:

by = -ax + c

y = -\dfrac{a}{b}x + \dfrac{c}{b}

The slope is -a/b.

Now look at your system of equations. The slope of the first equation is -a/b = -2/3. The slope of the second equation is -a/b = -6/5.

You have a system of two linear equations with two lines with different slopes, so the lines must intersect at a single point.

Answer: the system has a unique solution

5 0
3 years ago
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