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Paladinen [302]
3 years ago
11

Seth purchased a printer for $350. The price of the printer that Jose purchased was 4/5 the price that Seth payed. How much did

Jose pay?
Mathematics
1 answer:
Natasha2012 [34]3 years ago
3 0
4/5 of 350...." of " means multiply
4/5(350) = 1400/5 = 280 <== Jose payed $ 280
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36 kg bag of cement was dropped losing one tenth of cement. How much was left in the bag of cement ?
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Answer:

32.4kg

Step-by-step explanation:

if it loses one tenth of cement;

36kg×1/10

36kg/10

3.6kg was lost

to find the remaining ; 36kg - 3.6kg = 32.4kg is left in the bag

7 0
3 years ago
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3. You want to have $4000 in your savings account after 2 years. Find the amount you should deposit for each of the situations d
pychu [463]

Answer:

Part A)

About $3767.34.

Part B)

About $3692.47.

Step-by-step explanation:

Part A)

Recall that compound interest is given by the formula:
\displaystyle A = P\left(1+\frac{r}{n}\right)^{nt}

Where <em>A</em> is the final amount, <em>P</em> is the initial amount, <em>r</em> is the interest rate, <em>n</em> is the number of times compounded per year, and <em>t</em> is the number of years.

To obtain $4000 after two years, let <em>A</em> = 4000 and<em> t</em> = 2.

Because the account pays 3% interest compounded monthly, <em>r</em> = 0.03 and <em>n</em> = 12.

Substitute and solve for <em>P: </em>

<em />\displaystyle \begin{aligned} (4000) & = P\left(1+\frac{(0.03)}{(12)}\right)^{(12)(2)} \\ \\ P & = \frac{4000}{\left(1+\dfrac{(0.03)}{(12)}\right)^{(12)(2)}} \\ \\ & \approx \$3767.34\end{aligned}

In concluion, about $3767.34 should be deposited.

Part B)

Recall the formula for continuous compound:

\displaystyle A = Pe^{rt}

Where <em>e</em> is Euler's number.

Hence, let <em>A</em> = 4000, <em>r</em> = 0.04 and <em>t</em> = 2. Substitute and solve for <em>P: </em>

<em />\displaystyle \begin{aligned}(4000) & = Pe^{(0.04)(2)} \\ \\ P & = \frac{4000}{e^{(0.02)(4)}} \\ \\ & \approx \$3692.47 \end{aligned}

In conclusion, about $3692.47 should be deposited.

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