25d^2-30d-35d+42=25d^2-65d+42.
Answer:
49
Step-by-step explanation:
43 +4 make sure you add them
47 +2
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49
Answer:
![\sqrt[3]{9}= 2.08008...](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B9%7D%3D%202.08008...)
Step-by-step explanation:
I used a calculator but 9 is not a perfect cube
The length and width of the rug is 20 and 11 feet respectively
The given parameters;
dimension of the room = 19 ft by 28 ft
maximum area of rug she can afford = 220 ft²
For a uniform stripe of floor around the rug, then suppose the uniform excess length of the floor to removed from each dimension = y
(28-2x)(19-2x)=220
532-94x+4x^2=220
4x^2-94x+312=0
x=39/2,4
For x=39/2, dimensions are negative.
The uniform dimension of the floor to be covered by the maximum area of rug she can afford = (28 - 4×2) and (19 -2×4 ) = 20 and 11
Thus, the dimensions of the rug should be 20 feet and 11 feet
- The area of a rectangle is length times breadth.
- Area is the total squares cm occupied by a closed figure.
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