Question

A rectangular yard measures 42 ft By 72 ft Is murdered and surrounded by a fence inside a walk that is 4 feet wide goes All the way along the fence find the area of the walk Be sure to include the correct unit in the answer

Answer 1

The area of the walk is 440$ft^{2}$.

Step-by-step explanation:

We have , a rectangular yard measures 42 ft By 72 ft Is murdered and surrounded by a fence inside a walk that is 4 feet wide goes All the way along the fence. That means we have a rectangle with dimensions of 42 ft by 72 ft and another rectangle that is concentric with dimensions less than 4 ft by previous rectangle i.e. (42-4) ft by (72-4) ft , which is 38 ft by 68 ft.

Now, we know that area of rectangle  = $length (breadth)$

Area of bigger rectangle  = $length (breadth)$

⇒$Area1 = 42(72) ft^{2}$

⇒$Area1 = 3024ft^{2}$

Similarly, Area of enclosed rectangle  = $length (breadth)$

⇒$Area2 = 38(68)ft^{2}$

⇒$Area2 = 2584ft^{2}$

Now, the area of walk = $Area1-Area2$

⇒ area of walk = $(3024-2584)ft^{2}$

⇒ area of walk = $440ft^{2}$

∴ The area of the walk is 440$ft^{2}$.