HELP PLEASE!!!!!!! IM TIREDD AND AM STUCK ON THIS LAST QUESTION THAT IVE BEEN WORKIGN ON FOR 20 MINUTES

Mathematics

1 answer:

avanturin [10]3 years ago

7 0

Answer:

1/3

Step-by-step explanation:

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A life guard in a tower 20 ft above sea level spots a struggling surfer at an angle of depression of 15 . How far is the surfer

GalinKa [24]

Answer: $19.31\ ft$

Step-by-step explanation:

Given

The tower is at a height of $h=20\ ft$

the angle of depression is $15^{\circ}$

Suppose the surfer is x ft away from the base of the tower

$\therefore \text{From the figure, we can write}\\\\\Rightarrow \cos 15^{\circ}=\dfrac{x}{h}\\\\\Rightarrow x=h\cos 15^{\circ}\\\Rightarrow x=20\cos 15^{\circ}\\\Rightarrow x=19.31\ ft$

Therefore, the surfer is at a distance of 19.31 ft from the base of the tower.

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2 years ago

Harold plans to buy a $95 Father's Day present for his father, and the holiday

Greeley [361]

Answer:

December 1st

Step-by-step explanation:

Apex

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3 years ago

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Marvin lives in Stormwind City and works as an engineer in the city of Ironforge. In the morning, he has 333 transportation opti

sukhopar [10]

The event "Atleast once" is the complement of event "None".

So, the probability that Marvin teleports atleast once per day will the compliment of probability that he does not teleports during the day. Therefore, first we need to find the probability that Marvin does not teleports during the day.

At Morning, the probability that Marvin does not teleport = 2/3

Likewise, the probability tha Marvin does not teleport during evening is also 2/3.

Since the two events are independent i.e. his choice during morning is not affecting his choice during the evening, the probability that he does not teleports during the day will be the product of both individual probabilities.

So, the probability that Marvin does not teleport during the day = $\frac{2}{3}*\frac{2}{3}=\frac{4}{9}$