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ASHA 777 [7]
3 years ago
12

How to simply this radical

Mathematics
1 answer:
kondor19780726 [428]3 years ago
4 0
16✔️75
16✔️25 • 3
16 • 5 • ✔️3
80✔️3.

The radical can be simplified to 80✔️3.
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W(n)=n-1; find w-(4)
loris [4]

Answer:5

Step-by-step explanation:

w(n)=4-1

=5

6 0
3 years ago
Let v = (v1, v2) be a vector in R2. Show that (v2, −v1) is orthogonal to v, and use this fact to find two unit vectors orthogona
andrey2020 [161]

Answer:

a. v.v' = v₁v₂ -  v₁v₂ = 0 b.  (20, -21)/29 and  (-20,21)/29

Step-by-step explanation:

a. For two vectors a, b to be orthogonal, their dot product is zero. That is a.b = 0.

Given v = (v₁, v₂) = v₁i + v₂j and v' =  (v₂, -v₁) = v₂i - v₁j, we need to show that v.v' = 0

So, v.v' = (v₁i + v₂j).(v₂i - v₁j)

= v₁i.v₂i + v₁i.(- v₁j) + v₂j.v₂i + v₂j.(- v₁j)

= v₁v₂i.i - v₁v₁i.j + v₂v₂j.i - v₂v₁j.j

i.i = 1, i.j = 0, j.i = 0 and j.j = 1

So, v.v' = v₁v₂i.i - v₁v₁i.j + v₂v₂j.i - v₂v₁j.j  

= v₁v₂ × 1 - v₁v₁ × 0 + v₂v₂ × 0 - v₂v₁ × 1

= v₁v₂ - v₂v₁

=  v₁v₂ -  v₁v₂ = 0

So, v.v' = 0

b. Now a vector orthogonal to the vector v = (21,20) is v' = (20,-21).

So the first unit vector is thus a = v'/║v'║ = (20, -21)/√[20² + (-21)²] = (20, -21)/√[400 + 441] = (20, -21)/√841 = (20, -21)/29.

A unit vector perpendicular to a and parallel to v is b = (-21, -20)/29. Another unit vector perpendicular to b, parallel to a and perpendicular to v is thus a' = (-20,-(-21))/29 = (-20,21)/29

8 0
2 years ago
(take 2 bc i messed up) What is √30 simplified
nignag [31]

Answer: the square root of 30 is simplified to 5...

Hope this helps! :D

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What does number one mean of letter b
soldier1979 [14.2K]

Answer:

M, N, O

Step-by-step explanation:

This line contains the letter "M"

6 0
3 years ago
NEED HELP ASAP
stellarik [79]

C

because you just eliminate it

3 0
3 years ago
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