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3 years ago

8

Write an equation in point-slope form, y – y1 = m(x – x1), of the line through points (1, –8) and (9, 8) Use (1, –8) as the poin

t (x1, y1).
A (y – 8) = –2(x + 1)

B (y – 8) = 2(x + 1)

C (y + 8) = –2(x – 1)

D (y + 8) = 2(x – 1)

1 answer:

Sphinxa [80]3 years ago

4 0

Answer:

it is C

Step-by-step explanation:

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The cost of renting roller blades is $4 plus $3.50 for each hour that the roller blades are rented. Write an expression to repre

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Answer:

The expression is equal to $3.50h+4$

Step-by-step explanation:

Let

x ----> the number of hours that the roller blades are rented

y ----> the cost of renting roller blades in dollars

we know that

The linear equation in slope intercept form is equal to

$y=mx+b$

where

m is the slope or unit rate of the linear equation

b is the y-intercept or initial value of the linear equation

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$m=\$3.50\ per\ hour$

The y-intercept is equal to

$b=\$4$ ----> value of y when the value of x is equal to zero

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$y=3.50x+4$

For x=h hours

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$y=3.50h+4$

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Two lines intersecting at a right angle ?

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Answer:

are perpendicular

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How would you solve for the question below???<br> step by step please and thanks.

Airida [17]

Combine the two equations in the right amounts to eliminate y :

-2 (2x + 3y) + (3x + 6y) = -2 (17) + 30

-4x - 6y + 3x + 6y = -34 + 30

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2 years ago

(i) 3 (a + 5b) + a (a + 4) (ii) y (10 - y) + 3 (y - 2) (iii) 2 (8a - 5b) + 3 (5a - 12) (iv) 3 (y - 3) + ( 8 - 6y + x) (v) a (a -

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Answer:

$3 (a + 5b) + a (a + 4) = a^2 + 7a + 15b$

$y (10 - y) + 3 (y - 2) = - y^2+13y - 6$

$2 (8a - 5b) + 3 (5a - 12) = 31a -10b - 36$

$3 (y - 3) + ( 8 - 6y + x) = -3y + x-1$

$a (a - 2b) + b (b + 2a - c) =a^2 + b^2 - bc$

$5 (x - y + z) + (4x + 3y) =9x - 2y +5z$

Step-by-step explanation:

Solving (i):

$3 (a + 5b) + a (a + 4)$

Open brackets

$3 (a + 5b) + a (a + 4) = 3a + 15b + a^2 + 4a$

Collect like terms

$3 (a + 5b) + a (a + 4) = a^2 + 4a+3a + 15b$

$3 (a + 5b) + a (a + 4) = a^2 + 7a + 15b$

Solving (ii)

$y (10 - y) + 3 (y - 2)$

Open bracket

$y (10 - y) + 3 (y - 2) = 10y - y^2 + 3y - 6$

Collect like terms

$y (10 - y) + 3 (y - 2) = - y^2+10y + 3y - 6$

$y (10 - y) + 3 (y - 2) = - y^2+13y - 6$

Solving (iii)

$2 (8a - 5b) + 3 (5a - 12)$

Open bracket

$2 (8a - 5b) + 3 (5a - 12) = 16a -10b + 15a - 36$

Collect like terms

$2 (8a - 5b) + 3 (5a - 12) = 16a+ 15a -10b - 36$

$2 (8a - 5b) + 3 (5a - 12) = 31a -10b - 36$

Solving (iv)

$3 (y - 3) + ( 8 - 6y + x)$

Open bracket

$3 (y - 3) + ( 8 - 6y + x) = 3y - 9 + 8 - 6y + x$

Collect like terms

$3 (y - 3) + ( 8 - 6y + x) = 3y - 6y + x- 9 + 8$

$3 (y - 3) + ( 8 - 6y + x) = -3y + x-1$

Solving (v):

$a (a - 2b) + b (b + 2a - c)$

Open bracket

$a (a - 2b) + b (b + 2a - c) =a^2 - 2ab + b^2 + 2ab - bc$

Collect like terms

$a (a - 2b) + b (b + 2a - c) =a^2 + 2ab- 2ab + b^2 - bc$

$a (a - 2b) + b (b + 2a - c) =a^2 + b^2 - bc$

Solving (vi)

$5 (x - y + z) + (4x + 3y)$

Open brackets

$5 (x - y + z) + (4x + 3y) =5x - 5y +5z+4x +3y$

Collect like terms

$5 (x - y + z) + (4x + 3y) =5x +4x +3y- 5y +5z$

$5 (x - y + z) + (4x + 3y) =9x - 2y +5z$

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3 years ago

An elevator began in the 9th floor. It went down 7 floors. Then, it went up 4 floors. On which floor did it stop?

nordsb [41]

The answer is floor number 6

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