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3 years ago

14z - 3-6-52) What is the answer to this ?

Mathematics

1 answer:

Viktor [21]3 years ago

8 0

Answer:

4.36

Step-by-step explanation:

14z-3-6-52 (Add all the numbers with the negative sign together)

= 14z-61 (Equation equals 0)

0 = 14z - 61 (Add 61 to zero)

0+61 = 14z ( Note :- the negative sign before 61 changes to +ve upon moving to the left hand side)

61 = 14z (Divide both sides by 14)

61/14 = 14/14

4.357 = z

z = 4.36

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This week Andres will practice with his band for 1 1\2 hours monday , 1 3\4 hours on tuesday , and 2 hours wednesday . Next week

alexdok [17]

Answer:

10.5 hours

Step-by-step explanation:

Given:

This week Andres will practice with his band for

$1\frac{1}{2} \ means\ \frac{3}{2} \ hours$ on Monday

$1\frac{3}{4} \ means\ \frac{7}{4} \ hours$ on Tuesday

2 hours Wednesday.

Next week Andres will practice with his band for the same number of hours on Monday, Tuesday, Wednesday.

Question asked:

What was the total number of hours Andres will practice with his band over these 6 days?

Solution:

As she practice for two weeks, three days of each week:

On two Monday, she will practice = $\frac{3}{2} + \frac{3}{2} =\frac{3+3}{2} =\frac{6}{2} =3\ hours$

On two Tuesday, she will practice = $\frac{7}{4} +\frac{7}{4}=\frac{7+7}{4} =\frac{14}{4} =\frac{7}{2} \ hours$

On two Wednesday, she will practice = $2+2=4 \ hours$

Total hours, she will practice over 6 days $=3+\frac{7}{2} +4$

$=7+\frac{7}{2} \\ \\ =\frac{2\times7+7}{2} \\ \\ =\frac{21}{2} \\ \\ =10.5\ hours$

Thus, Andres will practice 10.5 hours with his band over these 6 days.

5 0

3 years ago

ivolga24 [154]

Given:

Two jugs are similar. The smaller jug has radius 4 cm and the bigger jug has radius 6 cm and surface area 125 cm².

To find:

The area of the smaller jug.

Solution:

If two figures are similar, then the ratio of their areas is proportional to the square of the corresponding sides of the figures.

Two jugs are similar. So,

$\dfrac{\text{Area of smaller jug}}{\text{Area of bigger jug}}=\dfrac{(\text{Radius of smaller jug})^2}{(\text{Radius of bigger jug})^2}$

$\dfrac{\text{Area of smaller jug}}{125}=\dfrac{(4)^2}{(6)^2}$

$\dfrac{\text{Area of smaller jug}}{125}=\dfrac{16}{36}$

$\text{Area of smaller jug}=\dfrac{4}{9}\times 125$

$\text{Area of smaller jug}\approx 55.56$

Therefore, the area of the smaller jug is about 55.56 cm².

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