With
, we have identical PDFs

for
, and 0 otherwise, where

Since
are independent, the joint PDF is

for points
in the unit square, and 0 otherwise.
1. The distribution is continuous, so
.
2.
is the region in the
plane contained within the unit square and above the line
. This region is empty, because this line lies above the square altogether, so
.
3.
is the region in the same square below the line
. So we have

Answer:
a. An equilateral triangle main characteristic is that all the sides lenght are the same (s). To find the height (h), we could divide the triangle (as seen in the picture) and apply Pytagorean theorem.

Clearing the expression, we obtain: 
b. Knowing the rate at which the volume is changing 4
, we can find the relation between the change in the volume and the height.

As we want to express the volume in terms of the height, we have to find the area in terms of height

Base=s=
Therefore, 

Therefore the change in the volume with the height, will be the derivate of this expression

Knowing dV/dt=4 cubic feet per second, and h=1/2 foot, we can know dh/dt

Step-by-step explanation:
2y^2+4y-9 should be the answer
Option A:

Solution:
Given expression
.
To find the product of the above expression:

First multiply first two factors with each term.

Using exponent rule: 

Now multiply these two factors with each term.


Using exponent rule:



Hence option A is the correct answer.