<span>Think of arcsin (-1/3) as an angle, and call it "theta." The the original problem becomes "find sec [ 2 theta ]"
1 1
which is the same as "find ------------------ " or --------------------------------------
cos[2 theta] (cos theta)^2 - (sin theta)^2
Recall that theta = the angle whose sine is -1/3. Thus, sin theta = -1/3 and cos theta = 2sqrt(2) / 3.
So we now have:
1
-------------------------------------------
2 sqrt(2) -1
[------------------- ]^ 2 - [ ------- ]^2
3 3
which boils down to:
1 1
----------------- = ---------------- = 9/7 (answer)
8 1 7/9
------ - --------
9 9
</span>
Answer: 38 think
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
<em>x</em> is greater than 12:

and <em>x</em> is less than or equal to 3 times the value of y:

We can divide everything by 3:

Answer:
1215
Step-by-step explanation:
If you have a 25% or 1/4 increase, this would mean that you divided the total number of students and add the quotient to the main thing.
So: 972 divided by 1/4 = 972/4 = 243.
972 + 243 = 1215.