Question

Write an equation of the line that passes through (2,-3) and is perpendicular to the line y=-2x-3.

Answer 1

Step-by-step explanation:

y=2x-3

gradient=(x1-x2)+(y1-y2)

(2-3)is one line and y=2x-3 is another line

so, we work the second line that is y=2x-3

y=2(2)-3

it should look like this y=4-3

y=1

we now find the gradient

so we know gradient is (x1-x2) and (y1-y2)

so we fix the values in the equation

(2)(-3+1)

ur equation should look like this

(2)(-2)

the answer is -4