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muminat
2 years ago
15

What is the value of(3)^3 10

Mathematics
1 answer:
torisob [31]2 years ago
4 0
If the 10 is being multiplied it’s 90
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Which problem can be solved using this inequality?<br> x + 5 ≤ 20
Fed [463]

Answer:

Beth is purchasing school supplies. She knows that the price for her pencil case is $5. She only has $20 to spend. What is the most amount of money she can spend on the remaining supplies?

Step-by-step explanation:

b

20 dollars is the whole value of the right side of the inequality that is greater or equal to x+5

3 0
3 years ago
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Complete the conversion. Enter your answer in the box.<br> 8 pt = __ c
Shtirlitz [24]

Answer:

16 cups

Step-by-step explanation:

there are 2 cups in a pint

8x 2= 16

7 0
3 years ago
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Anna is making a banner out of 4 congruent triangles as shown below. How much blue trim will she need for each side
Ede4ka [16]

Answer:

The length of each blue trim is 17.2 inches

Step-by-step explanation:

Given

See attachment for banner

Required

The length of each blue trim

Since all 4 triangles are equal, then the dimension of 1 triangle is:

Side\ 1 = 10

Side\ 2 = 14

The hypotenuse (x) of the triangle blue trim is represented by the blue trim

So:

x^2 = Side\ 1^2 + Side\ 2^2

This gives

x^2 = 10^2 + 14^2

x^2 = 100 + 196

x^2 = 296

Take square root

x = \sqrt{296

x = 17.2in

3 0
3 years ago
Consider the following equation of the form dy/dt = f(y)dy/dt = ey − 1, −[infinity] &lt; y0 &lt; [infinity](a) Sketch the graph
kotegsom [21]

Complete Question:

The complete question is shown on the first uploaded image

Answer:

a) The graph of  f(y) versus y. is shown on the second uploaded image

b) The critical point is at y = 0  and the solution is asymptotically unstable.

c)The phase line is shown on the third uploaded image

d) The sketch for the several graphs of solution in the ty-plane  is shown on the fourth uploaded image

Step-by-step explanation:

Step One: Sketch The Graph of  f(y) versus y

Looking at the given differential equation

       \frac{dy}{dt} = e^{y} - 1 for -∞ < y_{o} < ∞

 We can say let \frac{dy}{dt} = f(y) =e^{y} - 1

Now the dependent value is f(y) and the independent value is y so to sketch is graph we can assume a scale in this case i cm on the graph is equal to 2 unit for both f(y) and y and the match the coordinates and after that join the point to form the graph as shown on the uploaded image.

Step Two : Determine the critical point

   To fin the critical point we have to set   \frac{dy}{dt} = 0

       This means e^{y} - 1 = 0

                          For this to be possible e^{y} = 1

                          which means that  e^{y} = e^{0}

                          which implies that y = 0

Hence the critical point occurs at y = 0

meaning that the equilibrium solution is y = 0

As t → ∞, our curve is going to move away from y = 0  hence it is asymptotically unstable.

Step Three : Draw the Phase lines

A phase line can be defined as an image that shows or represents the way an ODE(ordinary differential equation ) that does not explicitly depend on the independent variable behaves in a single variable. To draw this phase line , draw the y-axis as a vertical line and mark on it the equilibrium, i.e. where  f(y) = 0.

In each of the intervals bounded  by the equilibrium draw an upward

pointing arrow if f(y) > 0 and a downward pointing arrow if f(y) < 0.

      This phase line would solely depend on y does not matter what t is

On the positive x axis it would get steeper very quickly as you move up (looking at the part A graph).

For  below the x-axis which stable (looking at the part a graph) we are still going to have negative slope but they are going to be close to 0 and they would take a little bit longer to get steeper  

Step Four : Draw a Solution Curve

A solution curve is a curve that shows the solution of a DE (deferential equation)

Here the solution curve would be drawn on the ty-plane

So the t-axis(x-axis) is its the equilibrium  that is it is the solution

If we are above the x-axis it is going to increase faster and if we are below it is going to decrease but it would be slower (looking at part A graph)

5 0
2 years ago
If Jaime is riding at 14 miles per hour and Cori is riding at 0.40 km per minute, how far will each of them bike in two hours? 1
user100 [1]

Answer:

just take speed =distance ÷time

dustance is speedxtime

14x1.61=22.54÷60 to change to min =0.37km per minute

0.40x0.37= 0.148 km

perhaps I may get wrong

5 0
2 years ago
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