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2 years ago

13

How can you know if the person or organization providing the information has the credentials and knowledge to speak on this topi

c? One clue is the type of web site it is--the domain name ".org" tells you that this site is run by a nonprofit organization.

Computers and Technology

1 answer:

Minchanka [31]2 years ago

7 0

Answer:

The affiliation of the writer is that She is on the staff at the Center for Food Safety (CFS).

Explanation:

CFS stands for the Center for Food Safety which is the national non-profitable public environmental and interest advocacy organization that is working for protect the human health and environment by the curbing use of the harmful food productions technologies and by the promoting an organic and other form of the sustainable agriculture.

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3 years ago

There are 12 inches in a foot and 3 feet in a yard. Create a class named InchConversion. Its main() method accepts a value in in

Dafna1 [17]

Answer:

import java.util.Scanner;

public class InchConversion

{

public static void main(String[] args) {

Scanner input = new Scanner(System.in);

System.out.print("Enter inches: ");

double inches = input.nextDouble();

inchesToFeet(inches);

inchesToYards(inches);

}

public static void inchesToFeet(double inches){

double feet = inches / 12;

System.out.println(inches + " inches = " + feet + " feet");

}

public static void inchesToYards(double inches){

double yards = inches / 36;

System.out.println(inches + " inches = " + yards + " yards");

}

}

Explanation:

In the inchesToFeet() method that takes one parameter, inches:

Convert the inches to feet using the conversion rate, divide inches by 12

Print the feet

In the inchesToYards() method that takes one parameter, inches:

Convert the inches to yards using the conversion rate, divide inches by 36

Print the yards

In the main:

Ask the user to enter the inches

Call the inchesToFeet() and inchesToYards() methods passing the inches as parameter for each method

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2 years ago

A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st

Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

$^nC_r = \frac{n!}{(n-r)!r!}$

Where $n = 15\ and\ r = 4$

$^{15}C_4 = \frac{15!}{(15-4)!4!}$

$^{15}C_4 = \frac{15!}{11!4!}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{32760}{24}$

$^{15}C_4 = 1365$

<em>Hence, there are 1365 ways </em>

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

<em>From the given parameters; 3 out of 15 is detective;</em>

So;

$p = 3/15$

$p = 0.2$

$q = 1 - p$

$q = 1 - 0.2$

$q = 0.8$

Solving further using binomial;

$(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n$

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

$Probability = ^nC_3pq^3$

Substitute 4 for n, 0.2 for p and 0.8 for q

$Probability = ^4C_3 * 0.2 * 0.8^3$

$Probability = \frac{4!}{3!1!} * 0.2 * 0.8^3$

$Probability = 4 * 0.2 * 0.8^3$

$Probability = 0.4096$

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

<em>Probability that at least one is defective + Probability that at none is defective = 1</em>

Probability that none is defective is calculated as thus;

$Probability = q^n$

Substitute 4 for n and 0.8 for q

$Probability = 0.8^4$

$Probability = 0.4096$

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

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