Please help with number 6 ASAP I will mark branlist

Mathematics

1 answer:

DerKrebs [107]3 years ago

5 0

Answer:

<h2>12</h2><h2>Step-by-step explanation:</h2>

$4\sqrt{9}\\\\\mathrm{Factor\:the\:number:\:}\:9=3^2\\=4\sqrt{3^2}\\\\\mathrm{Apply\:radical\:rule}:\quad \sqrt{a^2}=a,\:\quad \:a\ge 0\\\sqrt{3^2}=3\\\\=4\times\:3\\\\=12$

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