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Korolek [52]
3 years ago
12

Raportul a doua catete ale unui triunghi dreptunghic este de 3 supra 7,iar inaltimea este de 42cm.Aflati inaltimea,catetele,ipot

enuza si proiectiile inaltimii pe ipotenuza.
Mathematics
1 answer:
Basile [38]3 years ago
6 0

Answer:

could you write in in english

Step-by-step explanation:

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2/5 of house household own pets . Of the household pets 1/3 have cats. What is the fraction of the household own cats
fredd [130]

Fraction of household owning pets = \frac{2}{5}

Fraction \; of \; household \; owning \; cats \; \\\\=\; \frac{1}{3} \; of\; Fraction \; of\; household\; owning \; pets \\\\=\frac{1}{3}  \times\frac{2}{5}  \\ \\Multiply \; numerator\; with\; numerator\; and\; denominator\; with\; denominator\\\\=   \frac{1 \times 2}{3 \times 5}= \frac{2}{15}

Conclusion:

The fraction of the household own cats is <em>two-fifteenth </em>

4 0
3 years ago
Read 2 more answers
Help, will give Brainliest and five stars
frez [133]
Let's see if we can't be logical here......Pick a formula and see what it yields. For example, choose D.

For n = 1 ---> -1 x 4^1 ----> -1 x 4 = -4, when the correct value is 1. Therefore D is out.

Try C. For n = 1 ---> 1 x 4^(1-1) ---> 1 x 4^0 ----> 1 x1 ---> 1, So it is correct for n =1. How about
n=2? 1 x 4^(2-1) = 1 x 4^1 = 1 x 4 = 4, when the correct answer is -4. Therefore C is out

I'm sure you can do the remaining two choices....
8 0
4 years ago
Read 2 more answers
chris buys p pairs of pants and 4 more shirts than pairs of pants. Shirts cost $18 each and pair of pants cost $25 each. What do
jasenka [17]

p is the number of pants

25 is $25 for the pants

18 is $18 for the pants

4 represents that you bought 4 more shirts than pants

plz rate as brainliest answer

6 0
3 years ago
A metal hollow bar whose cross section and dimension are shown below weighs 8x10^3 kg/m^3 and measure 2m in length ..determine t
devlian [24]
1) We calculate the volume of a metal bar (without the hole).

volume=area of hexagon x length
area of hexagon=(3√3 Side²)/2=(3√3(60 cm)²) / 2=9353.07 cm²
9353.07 cm²=9353.07 cm²(1 m² / 10000 cm²)=0.935 m²

Volume=(0.935 m²)(2 m)=1.871 m³

2) we calculate the volume of the parallelepiped

Volume of a parallelepiped= area of the section  x length
area of the section=side²=(40 cm)²=1600 cm²
1600 cm²=(1600 cm²)(1 m² / 10000 cm²=0.16 m²
Volume of a parallelepiped=(0.16 m²)(2 m)=0.32 m³

3) we calculate the volume of a metal hollow bar:
volume of a metal hollow bar=volume of a metal bar -  volume of a parallelepiped

Volume of a metal hollow bar=1.871 m³ - 0.32 m³=1.551 m³

4) we calculate the mass of the metal bar

density=mass/ volume  ⇒ mass=density *volume

Data:
density=8.10³ kg/m³
volume=1.551 m³

mass=(8x10³ Kg/m³ )12. * (1.551 m³)=12.408x10³ Kg

answer: The mas of the metal bar is 12.408x10³ kg  or   12408 kg  


4 0
3 years ago
-c + -11c + -15 = 9<br> solve for c
Phoenix [80]
The answer to this question is c = -2
8 0
4 years ago
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