Answer:
In a certain Algebra 2 class of 30 students, 22 of them play basketball and 18 of them play baseball. There are 3 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?
I know how to calculate the probability of students play both basketball and baseball which is 1330 because 22+18+3=43 and 43−30 will give you the number of students plays both sports.
But how would you find the probability using the formula P(A∩B)=P(A)×p(B)?
Thank you for all of the help.
That formula only works if events A (play basketball) and B (play baseball) are independent, but they are not in this case, since out of the 18 players that play baseball, 13 play basketball, and hence P(A|B)=1318<2230=P(A) (in other words: one who plays basketball is less likely to play basketball as well in comparison to someone who does not play baseball, i.e. playing baseball and playing basketball are negatively (or inversely) correlated)
So: the two events are not independent, and so that formula doesn't work.
Fortunately, a formula that does work (always!) is:
P(A∪B)=P(A)+P(B)−P(A∩B)
Hence:
P(A∩B)=P(A)+P(B)−P(A∪B)=2230+1830−2730=1330
For line A, y=1/6x
For line C, y=-2/7x+9
For line B, y=-8
To draw a locus point you have to draw<span> the half way line through the two </span>points. You can do this by drawing<span> the line bisector through AB points. Just open your compass to ¾ of the distance AB and then </span>draw<span> two arcs from both sides of your line. Once this is done </span>draw the line passing through the two intersection points<span>.
Hope this helps :)</span>
The answer is y = 12x - 24
Use the form y = mx + b
If the points are (2, 0) and (3, 12) the slope is 12 which gives us m.
Since every time you go backwards once it goes down 12, (1, -12) is a point and then (0, -24) is a point that shows us the y-intercept which gives us b.
