Answer:
P=0.1147
Step-by-step explanation:
P(bow tie)=0.03
P(no bow tie)=0.97
n=4
![P(at \ least \ one)=1-P(none)\\=1-(1-0.03)^4\\=0.1147](https://tex.z-dn.net/?f=P%28at%20%5C%20least%20%5C%20one%29%3D1-P%28none%29%5C%5C%3D1-%281-0.03%29%5E4%5C%5C%3D0.1147)
Answer:
your answer should be d
Step-by-step explanation:
Answer:
![sin 240^\circ = - \dfrac{\sqrt{3}}{2}](https://tex.z-dn.net/?f=sin%20240%5E%5Ccirc%20%3D%20-%20%5Cdfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D)
Step-by-step explanation:
We are given that:
![sin 60^\circ = \dfrac{\sqrt{3}}{2}](https://tex.z-dn.net/?f=sin%2060%5E%5Ccirc%20%3D%20%5Cdfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D)
We need to find
![sin 240^\circ = ?](https://tex.z-dn.net/?f=sin%20240%5E%5Ccirc%20%3D%20%3F)
240 is greater than 180 and lesser than 270
OR
![180^\circ](https://tex.z-dn.net/?f=180%5E%5Ccirc%3C240%5E%5Ccirc%3C270%5E%5Ccirc)
So, Angle
lies in the 3rd quadrant and it is well known that value of sine in 3rd quadrant is negative.
Using the property :
or
![sin(180^\circ + \theta) = -sin\theta](https://tex.z-dn.net/?f=sin%28180%5E%5Ccirc%20%2B%20%5Ctheta%29%20%3D%20-sin%5Ctheta)
Here,
.
![sin 240^\circ =sin(180^\circ + 60^\circ) = -sin60^\circ\\\Rightarrow -\dfrac{\sqrt{3}}{2}](https://tex.z-dn.net/?f=sin%20240%5E%5Ccirc%20%3Dsin%28180%5E%5Ccirc%20%2B%2060%5E%5Ccirc%29%20%3D%20-sin60%5E%5Ccirc%5C%5C%5CRightarrow%20-%5Cdfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D)
Hence, the value
![sin 240^\circ = - \dfrac{\sqrt{3}}{2}](https://tex.z-dn.net/?f=sin%20240%5E%5Ccirc%20%3D%20-%20%5Cdfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D)
Answer:
c
Step-by-step explanation:
I did this last year
He can pack 2. In each group with 1 left over