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3 years ago

A computer repair service charges a one-time bench fee of $50 to diagnose the problem

Mathematics

1 answer:

polet [3.4K]3 years ago

4 0

Y=35x+50 bc you already have to pay 50$ and then you spend 35 a hour and the X represents how many hours.

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The height of an equilateral triangle is 13 feet. The triangles area is 39 feet squared. What is the perimeter of the triangle?

cluponka [151]

Answer:

It is 6ft

Step-by-step explanation:

The formula is

A= 1/2bh so now you would substitute

39= 1/2(13)h

78= 13h

6=h

8 0

3 years ago

16.2 Jumping Rope

slava [35]

Answer:

Percentage of Diego's time is 75%.

Step-by-step explanation:

Given : Jumping Rope hool held a jump-roping contest. Diego jumped rope for 20 minutes. A school held a jur Jada jumped rope for 15 minutes.

To find : What percentage of Diego's time is that?

Solution :

Diego jumped rope for 20 minutes.

Jada jumped rope for 15 minutes.

Percentage of Diego's time is given by,

$\text{Percentage change}=\frac{\text{Jada time}}{\text{Diego time}}\times 100$

$\text{Percentage change}=\frac{15}{20}\times 100$

$\text{Percentage change}=75\%$

Therefore, percentage of Diego's time is 75%.

7 0

2 years ago

I need help with this

Ulleksa [173]

No, tahts the answer

8 0

3 years ago

Each letter of the word ASSESSMENT is written on a card and placed in a bag. You are equally likely to get any card.

NARA [144]

Answer:

I would say getting four S would be more percent than the other letters in the assessment word. They have more chance, and more possibility.

Step-by-step explanation: Brainliest please

6 0

3 years ago

A circle has a radius of 7.5 centimeters and a central angle AOB that measures 90 degrees. What is the length of the intercepted

Julli [10]

Since there are $360^{\circ}$ in a circle, and central $\angle AOB = 90^{\circ}$ , you can see that the part "sliced out" by the central angle is $\frac{90^{\circ}}{360^{\circ}} = \frac{1}{4}$ of the whole circle.

This means that the length of the intercepted arc $\stackrel{\frown}{AB}$ is $\frac{1}{4}$ of the circumference of the circle. So,

$\stackrel{\frown}{AB} = \frac{1}{4}(2 \pi r) = \frac{1}{4}(2 \pi (7.5 cm)) = \bf \frac{15 \pi}{4} cm$

6 0

3 years ago