I'm assuming all of (x^2+9) is in the denominator. If that assumption is correct, then,
One possible answer is
Another possible answer is
There are many ways to do this. The idea is that when we have f( g(x) ), we basically replace every x in f(x) with g(x)
So in the first example above, we would have
In that third step, g(x) was replaced with x^2+9 since g(x) = x^2+9.
Similar steps will happen with the second example as well (when g(x) = x^2)
Answer with Step-by-step explanation:
We are given that an expression
We have to find domain restriction of the given function.
Domain restriction means : It is that value of x when substitute in function then function will not defined.
It means it is that values which makes denominator zero.
From given function we can see that
When substitute g=0 then it makes denominator zero.
Hence, the function is not defined at g=0
Substitute g=4
Then, it makes denominator zero.
Hence, function is not defined at g=4
Substitute g=2
Then,it makes denominator zero.
Hence, function is not defined at g=2
Therefore, the function is defined for all values of g except g=0, g=2 and g=4