Find all zeros of f(x)= x^3 + 3x^2 − 3x − 1
1 answer:
F(1) = 1^3 + 3(1)^1 - 3 - 1 = 1 + 3 - 3 - 1 = 0
so one zero is x = 1, and x-1 is a factor
dividing f(x) by x - 1 gives x^2 + 4x + 1
x = [-4 +/- sqrt (16 - 4)] / 2
x = -0.27, -3.73
zeroes are 1 , -0.27 and -3.73 Answer
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