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3 years ago

Find all zeros of f(x)= x^3 + 3x^2 − 3x − 1

1 answer:

4 0

F(1) = 1^3 + 3(1)^1 - 3 - 1 = 1 + 3 - 3 - 1 = 0

so one zero is x = 1, and x-1 is a factor

dividing f(x) by x - 1 gives x^2 + 4x + 1

x = [-4 +/- sqrt (16 - 4)] / 2

x = -0.27, -3.73

zeroes are 1 , -0.27 and -3.73 Answer

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What is the sum of 27 and r

Fudgin [204]

Answer:

27+r

Step-by-step explanation:

6 0

2 years ago

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Write in standard form (×+4)(×-5)=4 find the value of a,b,c

Alex17521 [72]

Answer:

$x^{2}$ - x - 24 = 0

a = 1

b = 1

c = -24

Step-by-step explanation:

(x + 4)(x - 5) = 4

x(x - 5) = $x^{2}$ - 5x

4(x - 5) = 4x - 20

$x^{2}$ - 5x + 4x - 20 = 4

$x^{2}$ - x - 20 = 4

$x^{2}$ - x - 20 - 4 = 0

$x^{2}$ - x - 24 = 0

a = 1

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3 years ago

Given that P = (-5, 5) and Q = (-13, 10), find the component form and magnitude of 2 vector PQ.

Brut [27]

Define unit vectors along the x-axis and the y-axis as $\hat{i} , \, \hat{j}$ respectively.

Then the vector from P to Q is
$\vec{PQ} = (-13+5)\hat{i} + (10-5)\hat{j} = -8\hat{i} + 5\hat{j}$
In component form, the vector PQ is (-8,5).

The magnitude of vector PQ is
√[(-8)² + 5²] = √(89) = 9.434

Answer:
The vector PQ is (-8, 5) and its magnitude is √89 (or 9.434).

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3 years ago

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Graph the data below and then answer the questions that follow. year 1=$20,000, year 2=$21,750, year 3=$23,500, year 4=$25,250,

Mariana [72]

Answer:

Since the difference between the value for each year is constant, this is an arithmetic sequence.

Step-by-step explanation:

Year 2 - Year 1 = 21,750 - 20,000 = 1,750

Year 3 - Year 2 = 23,500 - 21,750 = 1,750

Year 4 - Year 3 = Year 5 - Year 4 = 1,750

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2 years ago

If f(x)=4x^2+1 and g(x) = x^2-5 fins (f-g)(x)

arlik [135]

Answer:

Given:

f(x) = 4x² + 1

g(x) = x² - 5

Then

(f + g)(x) = 4x² + 1 + x² - 5

= 5x² - 4

Answer: 5x² - 4

5 0

3 years ago