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4 years ago

Find the value of x rounded to the nearest tenth

Mathematics

1 answer:

Tomtit [17]4 years ago

8 0

The figure suggests that the two sub-triangle are similar, because they are both right and the angle at the top is the same.

If that is the case, we can claim that the correspondent sides are in proportion:

$6\div 9 = x \div 8$

Solving for x we have

$x = \dfrac{6\cdot 8}{9}=\dfrac{48}{9}=\dfrac{16}{3}$

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What is 78.852 rounded to the nearest tenth?

Leviafan [203]

Answer:

78.9

Step-by-step explanation:

sense the hundredth place is 5 or higher

7 0

3 years ago

Read 2 more answers

State whether the triangles could be proven congruent, if possible, by SSS or SAS.

Helen [10]

Answer:

1. SSS

2. SAS

3. SAS

4. SSS

5. SAS

6. SAS

Step-by-step explanation:

1) Side FY ≅ Side CW Given

Side FP ≅ Side CM Given

Side YP ≅ Side MW Given

∴ΔMCW ≅ ΔFPY by the Side-Side-Side (SSS) rule of congruency

2) ∠CBD ≅ ∠BCA given that both are alternate interior angles

Side EB ≅ Side EC and Side DB ≅ Side CA Given

ΔBED ≅ ΔAEC by Side-Angle-Side (SAS) rule of congruency

3. ∠SVU ≅ ∠SVT Given

Side SV ≅ Side SV by reflexive property

Side VT ≅ Side VU Given

∴ ΔVSU ≅ ΔVST by Side-Angle-Side (SAS) rule of congruency

4. Side MN ≅ Side QP Given

Side MQ ≅ Side NP Given

Side NQ ≅ Side NQ by reflexive property

∴ΔQNM ≅ ΔQNP by the Side-Side-Side (SSS) rule of congruency

5. Indirect proof

Side GL ≅ Side HL Given

Side GJ ≅ Side HK Given

∠JLG ≅ ∠HLK vertically opposite angles

By sine rule

GJ/sin(∠JLG) = GL/n(∠GJL)

Similarly

HK/sin(∠HLK) = HL/n(∠HKL)

∴ ∠GJL ≅ ∠HKL

∴ ∠LGJ ≅ ∠LHK third angle of two triangles given the other two angles are congruent

∴ΔQNM ≅ ΔQNP by the Side-Angle-Side (SAS) rule of congruency

6. ∠XZY ≅ ∠XZW Supplementary ∠s with ∠XZY = 90°

Side XZ ≅ Side XZ by reflexive property

Side ZW ≅ Side ZY Given

∴ ΔXYZ ≅ ΔXWZ by Side-Angle-Side (SAS) rule of congruency.

3 0

3 years ago

Complex numbers, simplify the following expression; 10/1+3i

svp [43]

$\frac{10}{1 + 3i} = \frac{10}{1 + 3i} * \frac{1-3i}{1-3i} = \frac{10-30i}{1^{2} -(3i)^{2}} = \frac{10-30i}{1 -9 i^{2} } = \frac{10-30i}{1 -9*(-1)} = \frac{10(1-3i)}{1+9}= \frac{10(1-3i)}{10}$ $= 1 -3i$

8 0

4 years ago

Find the area of the composite figure. Round to the nearest tenth.

mihalych1998 [28]

Answer:

Surface area of figure = 200.52 meter²

Step-by-step explanation:

Given:

Side of square cut = 12 meter

Diameter of semi circle = 12 meter

Find:

Surface area of figure

Computation:

Diameter of semi circle = 12 meter

Radius of semi circle = Diameter of semi circle / 2

Radius of semi circle = 12 / 2

Radius of semi circle = 6 meter

Surface area of figure = Surface area of square + Surface of cylinder

Surface area of figure = [Side x Side] + πr²/2

Surface area of figure = [12 x 12] + (3.14)(6)²/2

Surface area of figure = [144] + (3.14)(36)/2

Surface area of figure = 144 + 56.52

Surface area of figure = 200.52 meter²

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3 years ago

How to estimate the square root of a number that is not a perfect square?

Goryan [66]

To estimate the square root of a number that is not a perfect square, you would find the perfect squares that the number is between and you know the square roots of those, so the answer will be somewhere between them. The closer you are to the number below the number you are estimating for, the smaller the decimal (_.1, _.2, etc.) and then it is opposite as you get closer to the number above the number you are estimating for.

6 0

3 years ago