We know that
sin(A + B) = sin A cos B + cos A sin B----> equation 1
sin(A − B) = sin A cos B − cos A sin<span> B----> equation 2
so
</span>tan A+tan B=[sin A/cos A]+[sin B/cos B]
=[(cos B*sin A)+(sin B*cos A)](cos A*cos B)
substitute equation 1
sin (A+B)/(cos A*cos B)
tan A-tan B=[sin A/cos A]-[sin B/cos B]
=[(cos B*sin A)-(sin B*cos A)](cos A*cos B)
substitute equation 2
sin (A-B)/(cos A*cos B)
[tan A+tan B]/[tan A-tan B]
=[sin (A+B)/(cos A*cos B)]/[sin (A-B)/(cos A*cos B)]
=[sin (A+B)/sin (A-B)]
hence
[tan A+tan B]/[tan A-tan B]=[sin (A+B)/sin (A-B)]
Answer:
-90
Step-by-step explanation:
10+5×5×(-2)
10+25×(-2)
10+(-100)
10-100
-90
<em>V</em>≈301.59
I think this is the answer.
Hope this helps!
Answer:
x = ¹⁴/9
Step-by-step explanation:
9x = 14
x = ¹⁴/9
_
x = 1.5
Answer:
63
Step-by-step explanation:
pie multiply 2 sq. 2 multiply with 5