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AlekseyPX
3 years ago
12

Find the least common denominator for these two rational expressions 7/n^2 -8/7n

Mathematics
1 answer:
lianna [129]3 years ago
8 0

Answer:

7n²

Step-by-step explanation:

7/n² - 8/7n

Least common multiple will be the least common denominator

L.C.M = 7n²

Dividing the L.C.M by denominators and multiplying with numerators;

((7×7) - (n×8))/7n²

= (49 - 8n)/7n²

7n² is the least common denominator

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weeeeeb [17]
the equivalent fraction is 6/8 is the answer
4 0
4 years ago
The following data was collected from a simple random sample of a population.
aivan3 [116]

Answer:

C

Step-by-step explanation:

This problem is analogous to the extraction of 6 elements from a total of 10 elements. It's the same if they are marbles, chips, or in this case, people, as here we don't care about the order of the selection as we only are drawing a sample.

Thus, the problem implies solving the amount of possible combinations of 10 people if we take by 6. There is a formula for this and is:

10 C 6 = 10!(6!4!)

If we operate, knowing that for any number x, x!=x*(x-1)*(x-2)*...*1

10 C 6 = 10!(6!4!) = 10*9*8*7*6*...*1 / [(6*5*...*1) * (4*3*2*1)]

10 C 6 = 10*9*8*7*6! / [(6*5*...*1) * (4*3*2*1)]

We have a 6! multiplying and another dividing, so they get eliminated, and as 4*2=8 and 9=3*3

10 C 6 = 10*9*8*7*/ [(4*3*2*1)] = 10*3*3*8*7*/ [(8*3*1)]

We can eliminate the 8s and one of the 3s on the numerator with the one on the denominator:

10 C 6 = 10*3*7*/1 = 210/1= 210

So, option C

5 0
3 years ago
Are their always the same number of prime numbers between 2 consecutive multiples of 10
Harlamova29_29 [7]

Yes there are. Its just the way they work out!

3 0
3 years ago
Factor completely 5x2 – 50x + 120
zaharov [31]
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                           = 5(x² - 10x + 24)
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                           = 5((x(x - 4) - 6(x - 4))
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5 0
3 years ago
Whats the equationbof the perpendicular line to y=3-0.25x that passes through the point (1,5)
valina [46]
Line of slope 4 and y_intercept 1
thus y=4x+1
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3 years ago
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