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Natasha_Volkova [10]
2 years ago
8

The solution set to an inequality is graphed on this number line. Which number(s) below belong to the solution set of the inequa

lity?
Check all that apply.
A. 47
B. 8
C. -99
D. 33
E. -10
F. 20

Mathematics
2 answers:
GuDViN [60]2 years ago
7 0

Answer:

8 , - 99 , -10 , 20  are solutions set of inequality.

Step-by-step explanation:

Given  : Number line .

To find : The solution set to an inequality is graphed on this number line. Which number(s) below belong to the solution set of the inequality.

Solution : We gave given a number line with solid dot at 20 and arrow on left side ( negative side).

We can say value of x start from -∞ to + 20.

So, value of x lies between -∞ to + 20.

Inequality become  x ≤ 20 .

So,

8 , - 99 , -10 , 20  are solutions set of inequality.

Therefore, 8 , - 99 , -10 , 20  are solutions set of inequality.

Drupady [299]2 years ago
3 0
Solution: (-∞,20]    or      x≤20

Answer: B.8, C.-99, E.-10 and F.20
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Use the functions to answer the question.
Lelechka [254]

Answer:

3 and 9

if f(x)=x^2+13 and g(x)=12x-14

Step-by-step explanation:

So when we are looking for the intersection of two functions, we are trying to figure out when they are the same.  When you think same, you should think equal (=).

So we want to find when f(x)=g(x) for x.

f(x)=g(x)

x^2+13=12x-14

Let's get everything to one side.

Subtracting 12x and adding 14 to both sides.

x^2+13+14-12x=0

I'm going to reorder the left hand side and also simplify the 13+14 part:

x^2-12x+27=0

Now since the coefficent of x^2 is just 1 our job is to find two numbers that multiply to be 27 and add up to be -12.

Those numbers are -3 and -9 since -3(-9)=27 and -3+(-9)=-12.

So the factored form of our equation is

(x-3)(x-9)=0

Since the product is 0, then at least one of the factors must be 0.

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x-9=9 can be solved by adding 9 on both sides. This gives us x=9.

The intersection of f and g happens at x=3 or x=9.

5 0
3 years ago
Read 2 more answers
The equation of motion for a weight suspended from a particular spring is given by p(t)=2sint3+5cost3p(t)=2sin⁡t3+5cos⁡t3, where
daser333 [38]
The given displacement at time, t, is
p(t) = 2 sin(t³) + 5 cos(t³)

The initial equilibrium position is
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Equilibrium is established when f(t) = 0.
To solve this equation numerically, we shall use the Newton-Raphson method, given by.
t(n+1) = t(n) - f[t(n)]/f'[(t(n)], n=0,1,2, ...,

As a guess, let (0) = 1.
The iterative solution for t is shown below.

  n         t(n)
 ---   -----------
   0   1.0000
   1    0.9344
   2   0.9147
   3   0.9130
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The solution converges rapidly to t = 0.913 s.
The graphical solution (shown below) confirms the numerical solution.

Answer:
The weight first reaches the equilibrium position in 0.913 sec.

4 0
3 years ago
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Answer:

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Step-by-step explanation:

48z+42q

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5 0
3 years ago
I’m just confused help!
rusak2 [61]

Answer:

Step-by-step explanation:

180

4 0
3 years ago
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