The correct answer is A.
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That is to protect Cell from external Harsh Environment
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Answer:
the correct sequence of the events happened during nerve impulse is (d): 2,1,4,3
Explanation:
Originally K+ ions remains inward the membranes while Na+ ions remains outward to maintain a resting potential of membrane.
Upon stimuli Sodium channels open on membrane and Na+ diffuses inward leading to the depolarization of membrane that is it becoming more positive due to Na+ and K+ ions.
To regain it polarized state or in repolarization state Potassium channels open and K+ begun to diffuse outward while Sodium channels gets closed and Na+ ions remains inside the membrane.
Potassium channels are not efficient as compared to Sodium Channels, so an excess amount of K+ion move outward so Hyperpolarization state achieved.
As the both ions are on the wrong side and will not be available for the next nerve impulse. Hence in Refractory period by the help of Na+/K+ pum, both ions move back to their original place and membrane achieve its resting membrane potential state.
The process of osmosis is the movement of water through a selectively permeable membrane from an area of higher concentration to an area of lower concentration.
If 1% sugar solution is placed in pure water, then there would be a higher concentration of water molecules outside the cell compared to inside the cell. The solution outside the cell would be hypo-tonic (containing fewer solute molecules than inside the cell). Water will move into the cell by inward osmosis and the cell would then swell.
