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Kazeer [188]
3 years ago
5

Which cream cheese has the lowest price per ounce?

Mathematics
2 answers:
kotykmax [81]3 years ago
8 0

Answer:

its b

Step-by-step explanation:

i did this

prohojiy [21]3 years ago
8 0

Answer:

i think it is B

Step-by-step explanation:

You might be interested in
WILL GIVE BRAINLIEST AND 100 POINTS
Airida [17]

Answer:

Apologiabiology  Ambitious

v=vanilla

c=chocolate

A.

4v+c=45

v+c=27

b.

multiply 2nd equation by -1 and add to first

4v+c=45

-v-c=-27 +

3v+0c=18

3v=18

divide both sides by 3

v=6

sub bac

v+c=27

6+c=27

minus 6

c=21

21chocolate

6 vanila

Step-by-step explanation:

5 0
3 years ago
Since at t=0, n(t)=n0, and at t=∞, n(t)=0, there must be some time between zero and infinity at which exactly half of the origin
Airida [17]
Answer: t-half = ln(2) / λ ≈ 0.693 / λ

Explanation:

The question is incomplete, so I did some research and found the complete question in internet.

The complete question is:

Suppose a radioactive sample initially contains N0unstable nuclei. These nuclei will decay into stable nuclei, and as they do, the number of unstable nuclei that remain, N(t), will decrease with time. Although there is no way for us to predict exactly when any one nucleus will decay, we can write down an expression for the total number of unstable nuclei that remain after a time t:

N(t)=No e−λt,

where λ is known as the decay constant. Note that at t=0, N(t)=No, the original number of unstable nuclei. N(t) decreases exponentially with time, and as t approaches infinity, the number of unstable nuclei that remain approaches zero.

Part (A) Since at t=0, N(t)=No, and at t=∞, N(t)=0, there must be some time between zero and infinity at which exactly half of the original number of nuclei remain. Find an expression for this time, t half.

Express your answer in terms of N0 and/or λ.

Answer:

1) Equation given:

N(t)=N _{0} e^{-  \alpha  t} ← I used α instead of λ just for editing facility..

Where No is the initial number of nuclei.

2) Half of the initial number of nuclei: N (t-half) =  No / 2

So, replace in the given equation:

N_{t-half} =  N_{0} /2 =  N_{0}  e^{- \alpha t}

3) Solving for α (remember α is λ)

\frac{1}{2} =  e^{- \alpha t} 

2 =   e^{ \alpha t} 

 \alpha t = ln(2)

αt ≈ 0.693

⇒ t = ln (2) / α ≈ 0.693 / α ← final answer when you change α for λ




4 0
3 years ago
(15 pts) 4. Find the solution of the following initial value problem: y"-10y'+25y = 0 with y(0) = 3 and y'(0) = 13
jolli1 [7]

Answer:

y(x)=3e^{5x}-2xe^{5x}

Step-by-step explanation:

The given differential equation is y''-10y'+25y=0

The characteristics equation is given by

r^2-10r+25=0

Finding the values of r

r^2-5r-5r+25=0\\\\r(r-5)-5(r-5)=0\\\\(r-5)(r-5)=0\\\\r_{1,2}=5

We got a repeated roots. Hence, the solution of the differential equation is given by

y(x)=c_1e^{5x}+c_2xe^{5x}...(i)

On differentiating, we get

y'(x)=5c_1e^{5x}+5c_2xe^{5x}+c_2e^{5x}...(ii)

Apply the initial condition y (0)= 3 in equation (i)

3=c_1e^{0}+0\\\\c_1=3

Now, apply the initial condition y' (0)= 13 in equation (ii)

13=5(3)e^{0}+0+c_2e^{0}\\\\13=15+c_2\\\\c_2=-2

Therefore, the solution of the differential equation is

y(x)=3e^{5x}-2xe^{5x}

5 0
3 years ago
Simplify the expression (2x − 9)(x + 6)
kenny6666 [7]

<u>Answer:  </u>

Simplified form of given expression (2x – 9 )( x + 6 )  is 2 \mathrm{x}^{2}+3 \mathrm{x}-54

<u> Solution: </u>

We need to simplify following expression.

(2x – 9) ( x + 6)  

For sake of simplicity lets first assume 2x – 9 = A

So expression becomes A(x+6)

= Ax + A6

Now replace A by 2x – 9

= (2x – 9 ) x + (2x – 9 ) 6

=2 \mathrm{x}^{2}-9 \mathrm{x}+12 \mathrm{x}-54

On simplification, we get

=2 \mathrm{x}^{2}+3 \mathrm{x}-54

Hence simplified form of given expression (2x – 9 )( x + 6 )  is = 2 \mathrm{x}^{2}+3 \mathrm{x}-54

7 0
3 years ago
Find the lowest terms<br> fraction that's equal<br> to 0.71.
Rudik [331]
71/100 is the lowest the fraction can get
7 0
3 years ago
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