Question

A rectangle has length X +5 and width X +4 if the perimeter of the rectangle is 42 m what are the length and width of the rectangle

Answer 1

The perimeter is 2(length) + 2(width), so 2(x+5) + 2(x+4) = 42 m. In solving for x, you find 6. Plug 6 back into your length and width where x originally was, and you find your length to be 11m, and your width to be 10m. Hope this helps!

Answer 2

Perimeter = 2(width + height)
42 = 2(x+5 + x+4)
 2x + 9 = 21
 2x = 12
   x = 6
Width = 11
Height = 10