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Marysya12 [62]
3 years ago
9

A rectangle has length X +5 and width X +4 if the perimeter of the rectangle is 42 m what are the length and width of the rectan

gle
Mathematics
2 answers:
Maru [420]3 years ago
6 0
The perimeter is 2(length) + 2(width), so 2(x+5) + 2(x+4) = 42 m. In solving for x, you find 6. Plug 6 back into your length and width where x originally was, and you find your length to be 11m, and your width to be 10m. Hope this helps!
krok68 [10]3 years ago
6 0
Perimeter = 2(width + height)
42 = 2(x+5 + x+4)
 2x + 9 = 21
 2x = 12
   x = 6
Width = 11
Height = 10
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Answer:

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Step-by-step explanation:

I think your question missed key information, allow me to add in and hope it will fit the orginal one

<em>For the graph below, what should the domain be so that the function is at least 200?   graph of y equals minus 2 times the square of x plus 30 times x plus 200 </em>

My answer:

Given the above information, we have:

y=-2x^2+30x+200

To make  the function is at least 200, it means that:

y=-2x^2+30x+200 ≥ 200

<=> -2x^2+30x ≥ 0

<=> x(-2x+30) ≥ 0

This is the product of two numbers hence would be positive only if either both are positive or both are negative

  • Case I: Both positive

x ≥ 0 and  (-2x+30) ≥ 0

<=> 0 ≤ x ≤ 15

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Then we get

x\leq 0 and -2x+30\leq 0\\\\x\leq 0 and x\geq 15

This is inconsistent as a value cannot be less than 0 and greater than 15

=> our correct answer is0\leq x\leq 15

Hope it will find you well.

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