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3 years ago

If you flip a coin or roll a 6-sided die, what is the probabilty that you will flip a tails and roll a 2?

Mathematics

1 answer:

telo118 [61]3 years ago

3 0

Answer:

$\frac{1}{12}$

Step-by-step explanation:

P(tail) = $\frac{1}{2}$

P(2) = $\frac{1}{6}$

P(tail and 2 ) = $\frac{1}{2}$ × $\frac{1}{6}$ = $\frac{1}{12}$

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Nadusha1986 [10]

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3 years ago

Consider the equation 2x+8y=12

rusak2 [61]

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3 years ago

The difference of three fifths of N and six.

vodomira [7]

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2 years ago

Applying Properties of Exponents In Exercise,use the properties of exponents to simplify the expression.

Mkey [24]

Answer:

$1.~e^{-2} \\2.~e^{\frac{7}{2}}\\3.~e^8\\4.~e^{\frac{-11}{2}}$

Step-by-step explanation:

We have to simplify the given exponential exponents.

Exponential Properties:

$e^0 =1\\e^a.e^b = e^{a+b}\\\\\displaystyle\frac{e^a}{e^b} = e^{a-b}\\\\(e^a)^b = e^{ab}\\\\e^{-a} = \frac{1}{e^a}$

Simplification takes place in the following manner:

$(e^{-3})^\frac{2}{3}\\(e^a)^b = e^{ab}\\=e^{-3\times \frac{2}{3}}\\=e^{-2}$

$(e^4)(e^{\frac{-1}{2}})\\e^a.e^b = e^{a+b}\\=e^{(4+\frac{-1}{2})} \\= e^{\frac{7}{2}}$

$(e^{-2})^{-4}\\(e^a)^b = e^{ab}\\= e^{-2\times -4}\\=e^8$

$(e^{-4})(e^{\frac{-3}{2}})\\e^a.e^b = e^{a+b}\\=e^{(-4+\frac{-3}{2})} \\= e^{\frac{-11}{2}}$

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3 years ago

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Marrrta [24]

Answer:

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2 years ago