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melamori03 [73]
3 years ago
6

Juan and his little brother Miguel ran around a circular track together. Juan ran on the inner track, which has a radius of 30 f

eet. Miguel ran on the outer track which has a radius of 40 feet. How much farther did Miguel run than Juan?
Mathematics
1 answer:
eduard3 years ago
8 0

Answer:

80pi-60pi

Step-by-step explanation:

To find how much Juan ran, we must find the circumference.

pi *30*2=60*pi  (which is how much Juan ran.)

pi*40*2=80*pi (which is how much Miguel ran)

80pi-60pi would be how much farther Miguel ran than Juan.

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A local theme park found that if the price of admission was $12 per person, the attendance for the week was 2200. When the price
dolphi86 [110]

You have two points

(12,2200) and (10,3000) You have enough information to set up an equation.

x1 = 12

x2 = 10

y1 = 2200

y2 = 3000

The slope = (y2 - y1)/ (x2 - x1)

The slope = (3000 - 2200) / (10 - 12)

Slope = 800 / - 2

slope = - 400

So far what you have is y = - 400x + b

To get b just use one of the points.

(10,3000)

y = - 400x + b

3000 = -400*10 + b

3000 = - 4000 + b Add 4000 to both sides.

3000 + 4000 = b

b = 7000

Answer y = - 400x + 7000

What happens if you use (12,2200)

y = -400*12+ 7000

y = - 4800 + 7000

y = 2200 As it should.

3 0
3 years ago
Motorola used the normal distribution to determine the probability of defects and the number
vovangra [49]

Answer:

a.P<x<9.85 orx>10.15)=0.3174, Total defects=317.4

b.p=0.0026,total defects=2.6

c.Less of the items produced will be classified as defects.

Step-by-step explanation:

a.The standard score,z, is esentially x reduced by process mean then divided my process standard deviation.

\mu=10,\sigma=0.15\\Therefore:-\\z=\frac{x-\mu}{\sigma}=\frac{9.85-10}{0.15}\approx-1.0\\z=\frac{x-\mu}{\sigma}=\frac{10.15-10}{0.15}\approx+1.0\\P(x10.15)=P(Z+1.0)\\=2P(Z

Total defects=Production*Probability

                      =0.3174*1000

                       =317.4

b. \mu=10,\sigma=0.05

therefore:-

z=\frac{x-\mu}{\sigma}=\frac{9.85-10}{0.05}\approx-3.0\\z=\frac{x-\mu}{\sigma}=\frac{10.15-10}{0.05}\approx+3.0\\\\=P(x10.15)=P(Z+3.0)\\=2P(Z

Defects=Probability*Production

            =0.0026*1000

             =2.6

c.Reducing process variation results in a significant reduction in the number of unit defects.

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3 years ago
What represents the number written as 23 and 37 thousandths
RSB [31]
.023
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13-16y is the same as -16y+13.

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-7r - 12 hope this helps
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