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Andrej [43]
3 years ago
7

What are two ways engineers use their understanding of kinetic energy and potential energy to make their designs better/ safer?

Physics
1 answer:
DanielleElmas [232]3 years ago
8 0

Answer:

On a roller coaster, energy changes from potential to kinetic energy and back again many times over the course of a ride. Kinetic energy is energy that an object has as a result of its motion. Traditionally, the coaster cars are pulled up the first hill by a chain; as the cars climb, they gain potential energy.

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How is an electric field similar to a gravitational field?
kap26 [50]
They both-
1) are vector fields
2) they both transmit forces between objects

I hope this helps :))
7 0
3 years ago
Read 2 more answers
Find the specific heat of a substance that requires 8000 J of energy to heat up 400g by 20 C?
monitta

Answer:

c=1\ J/g^\circ C

Explanation:

Given that,

Heat required, Q = 8000 J

Mass, m = 400 g

The change in temperature, \Delta T = 20^{\circ}

The heat required due to change in temperature is given by :

Q=mc\Delta T\\\\c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{8000 }{400\times 20}\\\\c=1\ J/g^\circ C

So, the specific heat of the substance is 1\ J/g^\circ C

7 0
3 years ago
In 1987, a gargantuan iceberg broke away from the Ross Ice Sheet in Antarctica. It was approximately a rectangle with dimensions
LUCKY_DIMON [66]

Explanation:

Below is an attachment containing the solution.

7 0
3 years ago
You attach a meter stick to an oak tree, such that the top of the meter stick is 1.87 meters above the ground. Later, an acorn f
Verdich [7]

To solve this problem we will apply the concepts related to the kinematic equations of linear motion. We will calculate the initial velocity of the object, and from it, we will calculate the final position. With the considerations made in the statement we will obtain the total height. Initial velocity of the acorn,

u = 0m/s

Also, it is given that the acorn takes 0.201s to pass the length of the meter stick.

s = ut+\frac{1}{2} at^2

Replacing,

1 = u(0.141)+ \frac{1}{2} (9.8)(0.141)^2

u =6.4013m/s

The height of the acorn above the meter stick can be calculated as,

v^2 = u^2 +2gh

h = \frac{v^2-u^2}{2g}

h = \frac{6.4013^2-0^2}{2(9.8)}

h = 2.0906m

Also the top of the meter stick is 1.87m above the ground hence the height of the acorn above the ground is

h = 2.0906+1.87

h = 3.9606m

4 0
4 years ago
If we know the total energy in a system is 30 J, and we know the PE is 20 J. What is the KE?
svetoff [14.1K]
Can you give more description ??

3 0
3 years ago
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