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sdas [7]
3 years ago
11

The equation x2 + 4y2 = 36 represents which conic section?

Mathematics
1 answer:
HACTEHA [7]3 years ago
3 0
<span>[x^2/36} + [y^2/9] = 1</span>
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The graph of the function f(x) is shown below.
faust18 [17]
Remember, parenthaees are like < and > and brackets ar like ≤ and ≥

domain is how far the x values go
x is left to right

we see they go from -3 to 5, with a filled in dot at -3 and empty dot at 5
means include -3 but not including 5
so like -3≤x<5
or in interval notation
[-3,5) is the domain



range
highest to lowest y value

range is from y=3 to y=-1
we gots full dots so we use brackets
range is [-1,3]



Domain=[-3,5)
Range=[-1,3]


B. read above and understand it
5 0
3 years ago
Resolute academy algebra 1
Goryan [66]

Answer:

B

Step-by-step explanation:

We can see in the expression that there are 2 x² blocks, 4 -x blocks, and 3 -1 blocks. Therefore, we can write this as

2 * x² + 4 * (-x) + 3 * (-1) = 2x²-4x-3

Comparing this with each answer, we have

A: x²-2x-4 + x² + 2x-1 = 2x²-5. This is not correct

B: 3x²-7x+1-(x²-3x+4) = 3x²-7x+1 -x²+3x-4 = 2x²-4x-3. This seems correct but we can check the other answers to be sure

C: (2x+1)(x-3) = 2x²-6x+x-3 = 2x²-5x-3. This is incorrect

D: \frac{8x^{12} - 16x^7 - 12x^6}{4x^6} = 2x^6 - 4x - 3. This is incorrect

3 0
3 years ago
To which graph does the point (−1, 3) belong? y ≥ 2x + 6 y ≥ 3x − 1 y ≥ −x + 3 y ≥ −2x + 5
Anna35 [415]
Well first find the slope of the point
y=mx+b  y=-1x+3
slope = -1
then put the problem in point slope form y - y1 = m (x-x1)
y + 3 = -1 (x+1) then solve for y=mx+b again
so y> 2x + 6 is the answer
4 0
3 years ago
Read 2 more answers
Find the distance between (3,4) and (4,-6) if necessary, round to the nearest tenth.
Ratling [72]

Answer:

The distance is:

d = 10.0 units (Rounded to the nearest the Tenths Place)

Step-by-step explanation:

Given the points

  • (3,4)
  • (4,-6)

The distance 'd' between (3,4) and (4,-6)

\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):

d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

substituting the points values

   =\sqrt{\left(4-3\right)^2+\left(-6-4\right)^2}

   =\sqrt{1+10^2}

   =\sqrt{1+100}

   =\sqrt{101}

   =10.0  units (Rounded to the nearest the Tenths Place)

Thus, the distance is:

d = 10.0 units (Rounded to the nearest the Tenths Place)

4 0
3 years ago
Which of the following does not describe slope?
kolbaska11 [484]
<span>a. A two-dimensional figure</span>
8 0
3 years ago
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