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Grace [21]
2 years ago
14

Isabella cures for an aquarium that is 6 feet long and has a height of 4 feet aquarium need 72 ft.³ of water to be completely fi

lled what is the width of the aquarium
Mathematics
2 answers:
Vanyuwa [196]2 years ago
8 0

Answer:

I'm going to take a guess and say the last part says what is width of the tank. Therefore, your answer is 3.

Step-by-step explanation:

The formula to find the volume of a rectangular cuboid is height (h) * length (l) * width (w), or h*l*w = volume (or ‘v’).

In this case, we already have the length and the height at 6 and 4, respectively, so we can plug that into our equation:

4*6*w = v

We also have the volume already figured out for us, so we can plug that in, too:

4*6*w = 72.

Now, all you need to do is simplify:

24 * w = 72

Divide both sides of the equation by 24 to isolate the value of the width:

w = 72/24

w = 3

So, there you have it! Since we were labeling our units in feet, in this case, the answer would be “The width of the aquarium is 3 feet”

Nataly [62]2 years ago
7 0

Answer

the answer is  w=3

Step-by-step explanation:

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Vadim26 [7]

The question is incomplete, here is the complete question:

The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.

When will there be less than 1 g remaining?

<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.

<u>Step-by-step explanation:</u>

All radioactive decay processes follow first order reaction.

To calculate the rate constant by given half life of the reaction, we use the equation:

k=\frac{0.693}{t_{1/2}}

where,

t_{1/2} = half life period of the reaction = 46 days

k = rate constant = ?

Putting values in above equation, we get:

k=\frac{0.693}{46days}\\\\k=0.01506days^{-1}

The formula used to calculate the time period for a first order reaction follows:

t=\frac{2.303}{k}\log \frac{a}{(a-x)}

where,

k = rate constant = 0.01506days^{-1}

t = time period = ? days

a = initial concentration of the reactant = 12.6 g

a - x = concentration of reactant left after time 't' = 1 g

Putting values in above equation, we get:

t=\frac{2.303}{0.01506days^{-1}}\log \frac{12.6g}{1g}\\\\t=168.27days

Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.

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2 years ago
Sarah's biweekly salary is $1540 what is her of gross monthly salary
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Answer:

Step-by-step explanation:

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y = (-5/2)x-2

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