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alexandr1967 [171]
2 years ago
11

Select the two values of x that are roots of this equation.

Mathematics
1 answer:
Sunny_sXe [5.5K]2 years ago
7 0

Answer:

C and D

Step-by-step explanation:

x = 5 ± √25 - 8 / 2

= 5 ± √17 / 2

The correct options are C and D.

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Ridley bought 3 3/4 yards of blue fabric,12 5/6 yards of red fabric,and 7 2/3 yards of purple fabric.if she paid $7.50 per yard,
Amanda [17]

The fabric cost $181.875

Step-by-step explanation:

Blue fabric bought = 3 3/4 yards , change to improper fraction (4*3)+3/4 = 15/4 yards

Red fabric= 12 5/6 yards = 77/6 yards

Purple fabric= 7 2/3 yards= 23/3 yards

Find  total length of fabric bought, 15/4 +77/6 +23/3 =291/12 yards

Cost per yard= $7.50

Total cost will be, 291/12 * 7.50 =$ 181.875

Learn More

Cost : brainly.com/question/12878495

Keywords : cost, yard

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2 years ago
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Gre4nikov [31]

\bf \textit{arc's length}\\\\ s=r\theta ~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad radians\\ \cline{1-1} \theta =\frac{3\pi }{2}\\ s=\frac{5\pi }{2} \end{cases}\implies \cfrac{5\pi }{2}=r\cdot \cfrac{3\pi }{2}

\bf \cfrac{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{3~~\begin{matrix} \pi \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }\cdot \cfrac{5~~\begin{matrix} \pi \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}=r\implies \cfrac{5}{3}=r

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Let f(x)= x(2x-3)/(x+2)x. Find the domain, vertical and horizontal asymptote
Reptile [31]

Step-by-step explanation:

Domain of a rational function is everywhere except where we set vertical asymptotes. or removable discontinues

Here, we have

\frac{x(2x - 3)}{(x + 2)x}

First, notice we have x in both the numerator and denomiator so we have a removable discounties at x.

Since, we don't want x to be 0,

We have a removable discontinuity at x=0

Now, we have

\frac{2x - 3}{x + 2}

We don't want the denomiator be zero because we can't divide by zero.

so

x + 2 = 0

x =  - 2

So our domain is

All Real Numbers except-2 and 0.

The vertical asymptors is x=-2.

To find the horinzontal asymptote, notice how the numerator and denomator have the same degree. So this mean we will have a horinzontal asymptoe of

The leading coeffixent of the numerator/ the leading coefficent of the denomiator.

So that becomes

\frac{2}{1}  = 2

So we have a horinzontal asymptofe of 2

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