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Anettt [7]
3 years ago
5

From a bag containing 12 identical blue balls, y identical yellow balls, and no other balls, one ball will be removed at random.

If the probability is less than 2/5 that the removed ball will be blue, what is the least number of yellow balls that must be in the bag?
Mathematics
1 answer:
sineoko [7]3 years ago
7 0

There are y + 12 total balls in the bag. The probability of drawing a blue one is is 12/(y + 12), and the probability of drawing a yellow one is y/(y + 12). We're told that the probability of drawing a blue ball is less than 2/5, so

\dfrac{12}{y+12}

which tells us there must be at least 19 yellow balls in the bag.

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